Those would be the K values, with the pooled standard deviation set to 1. I am trying to get this on the basis of a normal(0,1) distribution. Now with unequal standard deviations, this would be trickier. First, you must change to TEST=DIFF_SATT to get unequal variances per group. Then, in the output, you'll see for each value of MEANDIFF a value called actual alpha and a power. The actual alpha is greater than the nominal 0.05 because Satterthwaite's approximation introduces a bias. In this case the mean difference is NOT in terms of one or the other input groupstddev values, but follows the approximation found in the Details section of the PROC POWER documentation.
standard error of the difference = sqrt (sone * sone/none + stwo*stwo/ntwo), where sone is the standard deviation of group one, stwo is the standard deviation of group two, none is the number in group one, and ntwo is the number in group two. For your case, sone=1,none=24, stwo=2, ntwo=8, and standard error of the difference is sqrt(13/24)=0.74. So in this case, the mean differences are 0.2*standard error of the difference up to 2.4*standard error of the difference. You could plug in non-scaled values, if you have them.
SteveDenham
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