BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Barkamih
Pyrite | Level 9

Hi all 

 

I have data called fat, and it has variable PR and TEST DATE as well as COW ID. 

 Each cow has four test dates or more, and PR variable has four different levels. 

 

My question is I want to know the average number of test dates per cow for each PR level. 

 

someone told me it could be by using proc freq for cow id * pr, but I couldn't figure out that code

 

I hope you got my query 

 

Regards 

 

Ibrahim 

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

Example input data and example output for the given input really helps.

 

Here is an example of determining the average number of models of cars per make (or brand). You should have this data set to examine.

proc freq data=sashelp.cars noprint;
   tables make*type /out=makecount;
run;

proc means data=makecount mean;
  var count;
run;

 

 

The first step counts how many times combinations of  MAKE and TYPE appear in the data. In this case there is one record per MODEL.

Then average the resulting count. Which yields the average number of records for MAKE and type combinations.

I think that COWID would take the place of MAKE and TYPE would be your PR. Which would give the average number of records per cow and pr.

 

If you need something else, provide some small actual example data for input and the output you want for that input.

View solution in original post

7 REPLIES 7
PGStats
Opal | Level 21

Please show an example of your data and the SAS code you have tried.

PG
Barkamih
Pyrite | Level 9
COW_ID	         CAL_TE	      CEA       PR       TEST_DATE
71988495	06/09/2011	1	4	10/01/2012
71988495	06/09/2011	1	4	02/02/2012
71988495	06/09/2011	1	4	06/03/2012
71988495	06/09/2011	1	4	05/04/2012
71988495	06/09/2011	1	3	05/05/2012
75170579	07/10/2013	1	3	15/01/2014
75170579	07/10/2013	1	2	12/12/2013
75170579	07/10/2013	1	1	15/11/2013
75170579	07/10/2013	1	3	10/06/2014
76506914	19/03/2012	3	4	08/08/2012
76506914	19/03/2012	3	1	28/06/2012
76506914	19/03/2012	3	1	19/04/2012
76506914	19/03/2012	3	4	29/05/2012
77966344	17/01/2012	2	3	14/03/2012
77966344	17/01/2012	2	2	03/05/2012
77966344	17/01/2012	2	1	05/04/2012
77966344	17/01/2012	2	3	01/06/2012
77966344	17/01/2012	2	2	01/09/2012
77966344	17/01/2012	2	4	07/07/2012
77966344	17/01/2012	2	1	01/08/2012
77966344	17/01/2012	2	3	04/10/2012
77966344	17/01/2012	2	1	03/11/2012
82867861	02/05/2011	3	1	03/02/2012
82985152	01/09/2011	2	2	02/07/2012
82985152	01/09/2011	2	2	01/06/2012
82985152	01/09/2011	2	2	02/04/2012
82985152	01/09/2011	2	2	02/05/2012
82985152	01/09/2011	2	2	02/01/2012
82985152	01/09/2011	2	3	01/02/2012
82985152	01/09/2011	2	3	01/03/2012
108172029	29/05/2011	1	3	02/02/2012
108172029	29/05/2011	1	3	09/03/2012
108279276	27/05/2011	1	1	08/03/2012
108279276	27/05/2011	1	2	06/01/2012
108279276	27/05/2011	1	3	03/02/2012
110186178	18/08/2011	1	3	11/01/2012
110186178	18/08/2011	1	3	09/02/2012
110186178	18/08/2011	1	4	13/03/2012
110186178	18/08/2011	1	4	11/06/2012
110186178	18/08/2011	1	4	16/04/2012
110186178	18/08/2011	1	1	14/05/2012
110206340	13/11/2011	1	1	29/08/2012

Hi

 

this is my data, I didn't use any coed, but I just tried to use the normal proc freq as pr * cow_id, but it doesn't work. 

 

regards 

 

 

 

ballardw
Super User

@Barkamih wrote:

Hi all 

 

I have data called fat, and it has variable PR and TEST DATE as well as COW ID. 

 Each cow has four test dates or more, and PR variable has four different levels. 

 

My question is I want to know the average number of test dates per cow for each PR level. 

 

someone told me it could be by using proc freq for cow id * pr, but I couldn't figure out that code

 

I hope you got my query 

 

Regards 

 

Ibrahim 


"COW ID" is not normally  acceptable as a SAS variable name, spaces are not allowed.

So first check on the names of your variables.

You should show the code you attempted and any notes or messages from the LOG when things aren't working correctly.

Copy the text from the log, open a code box one the forum using the {I} icon and paste the code and any messages.

Barkamih
Pyrite | Level 9

thanks for your replay, I knew the space issue, what I'm looking is how to create the proper code for this question,   I didn't use any code yet except the proc freq code as cow_id * pr, but it doesn't work, actually, it worked but I didn't get my needs. 

 

thanks again 

 

regards 

Barkamih
Pyrite | Level 9

this code just showing the frequency of cow_id, but I'm looking for the average number of cow_id of all data. 

ballardw
Super User

Example input data and example output for the given input really helps.

 

Here is an example of determining the average number of models of cars per make (or brand). You should have this data set to examine.

proc freq data=sashelp.cars noprint;
   tables make*type /out=makecount;
run;

proc means data=makecount mean;
  var count;
run;

 

 

The first step counts how many times combinations of  MAKE and TYPE appear in the data. In this case there is one record per MODEL.

Then average the resulting count. Which yields the average number of records for MAKE and type combinations.

I think that COWID would take the place of MAKE and TYPE would be your PR. Which would give the average number of records per cow and pr.

 

If you need something else, provide some small actual example data for input and the output you want for that input.

Barkamih
Pyrite | Level 9

thank you soooooooo much my brother. 

 

I got the answer from this code. this requirement will be the last thing I was looking for to finish my first paper for publication.

 

thanks again 

 

I might need your help for the second paper, be always online hahahahah.

 

 

best regards 

 

Brakamih 

SAS Innovate 2025: Save the Date

 SAS Innovate 2025 is scheduled for May 6-9 in Orlando, FL. Sign up to be first to learn about the agenda and registration!

Save the date!

What is ANOVA?

ANOVA, or Analysis Of Variance, is used to compare the averages or means of two or more populations to better understand how they differ. Watch this tutorial for more.

Find more tutorials on the SAS Users YouTube channel.

Discussion stats
  • 7 replies
  • 1636 views
  • 0 likes
  • 3 in conversation