I have a table with tree_no, cumvol_dob variables.
I would like to know how to get the totvol_dob variable from cumvol_dob by tree_no in data step.
Any feedback would be greatly appreciated.
Thank you for your help.
Try this code and replace "have" with your dataset name.
proc sort data=have out=one;
by tree_no cumvol_dob;
run;
data two(keep=tree_no totvol_dob);
set one;
by tree_no;
totvol_dob=cumvol_dob;
if last.tree_no then output;
run;
data want;
merge have two;
by tree_no;
run;
proc print data=want;
run;
Hi,
I am assuming that "have" is the name of above data set. Try this for the desired solution.
Thanks,
data one;
set have;
flag = (tree_no=1);
if flag=1 then n+1;
run;
proc sort data=one out=two;
by n cumvol_dob;
run;
data three (keep=n totvol_dob);
set two;
by n cumvol_dob;
totvol_dob=cumvol_dob;
if last.n then output;
run;
data want(drop=n flag);
merge one three;
by n;
run;
Hi,
Can you please share your data as an attachement?
Thanks,
/* To make a group variable*/
data have;
set have;
group+(var-lag(tree_no) ne 1);
run;
proc sql;
create table want as
select *, max(cumvol_dob) as totvol_dob
from test
group by tree_no;
quit;
Haikuo
I found a mistake on my first post. I am sorry for that and thanks for your understanding.
How can I get to the totvol_dob variable from cumvol_dob as shown below?
tree_no | bolt_no | cumvol_dob | totvol_dob |
---|---|---|---|
1 | 5.849161048 | ||
1 | 1 | 2.128927995 | 5.849161048 |
1 | 2 | 3.844296214 | 5.849161048 |
1 | 3 | 5.849161048 | 5.849161048 |
2 | 1.127529281 | ||
2 | 1 | 0.623753528 | 1.127529281 |
2 | 2 | 1.127529281 | 1.127529281 |
3 | 1.316750698 | ||
3 | 1 | 0.48772395 | 1.316750698 |
3 | 2 | 0.865866814 | 1.316750698 |
3 | 3 | 1.316750698 | 1.316750698 |
How are you getting totvol_dob?
totvol_dob must be max of cumvol_dob
Try this code and replace "have" with your dataset name.
proc sort data=have out=one;
by tree_no cumvol_dob;
run;
data two(keep=tree_no totvol_dob);
set one;
by tree_no;
totvol_dob=cumvol_dob;
if last.tree_no then output;
run;
data want;
merge have two;
by tree_no;
run;
proc print data=want;
run;
Thanks stat@sas . It worked perfectly.
Proc sql is also great for this.
Just a caution, if the cumvol_dob that is the max isn't the last records, which it always is in the example data then stat@sas code above won't work.
proc sql;
create table want as
select a.*, max(cumvol_dob) as totvol_dob
from have
group by tree;
quit;
Thanks for the input Reeza. I coded this based on attached data.xls file. Actually data given above is different from the attached file.
Regards,
data have; input a b ; cards; 1 . 2 3.2 3 4.4 4 5.4 1 . 2 3.2 ; run; data have; set have; if a=1 then group+1; run; data want; do until(last.group); set have; by group; end; tot=b; do until(last.group); set have; by group; output; end; drop group; run;
Xia Keshan
Registration is now open for SAS Innovate 2025 , our biggest and most exciting global event of the year! Join us in Orlando, FL, May 6-9.
Sign up by Dec. 31 to get the 2024 rate of just $495.
Register now!
ANOVA, or Analysis Of Variance, is used to compare the averages or means of two or more populations to better understand how they differ. Watch this tutorial for more.
Find more tutorials on the SAS Users YouTube channel.