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gejoachim99
Fluorite | Level 6

I'm using ODA, trying to create a variable with this code - 

 

libname adeno '/home/u58566978/adeno';
data work.adeno1;
set adeno.finch_gjred;
run;

data work.adeno1;
set adeno.finch_gjred;
if beertotl=2 and beerfrq2=0 and beerfrqx2=0 and beernum2=98 then wrong=0;
if beertotl=3 and beerfrq3=0 and beerfrqx3=0 and beernum3=98 then wrong=0;
if beertotl=4 and beerfrq4=0 and beerfrqx4=0 and beernum4=98 then wrong=0;
if beertotl=5 and beerfrq5=0 and beerfrqx5=0 and beernum5=98 then wrong=0;
if beertotl=6 and beerfrq6=0 and beerfrqx6=0 and beernum6=98 then wrong=0;
if beertotl=7 and beerfrq7=0 and beerfrqx7=0 and beernum7=98 then wrong=0;
if beertotl=8 and beerfrq8=0 and beerfrqx8=0 and beernum8=98 then wrong=0;
if beertotl=9 and beerfrq9=0 and beerfrqx9=0 and beernum9=98 then wrong=0;
if beertotl=10 and beerfrq10=0 and beerfrqx10=0 and beernum10=98 then wrong=0;
if beertotl=11 and beerfrq11=0 and beerfrqx11=0 and beernum11=98 then wrong=0;
if beertotl=12 and beerfrq12=0 and beerfrqx12=0 and beernum12=98 then wrong=0;
else wrong=1;
run;

proc freq data=work.adeno1;
tables wrong;
run;

 

....but when I do that, this is the table I get. Screen Shot 2021-06-29 at 1.56.49 PM.pngWhen I exclude the 'else wrong=1' line, I get this, which is what I want, but I need to have a "1=832" line instead of those people being considered missing. Is this an ordering problem in my code? Any help is much appreciated. 

 

Screen Shot 2021-06-29 at 1.58.43 PM.png

1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26

Your ELSE is not correct. Try this:

 

libname adeno '/home/u58566978/adeno';
/*These next three lines not relevant to this problem, so I have commented them out */
/*data work.adeno1;*/
/*set adeno.finch_gjred;*/
/*run;*/

data work.adeno1;
    set adeno.finch_gjred;
    if beertotl=2 and beerfrq2=0 and beerfrqx2=0 and beernum2=98 then wrong=0;
    else if beertotl=3 and beerfrq3=0 and beerfrqx3=0 and beernum3=98 then wrong=0;
    else if beertotl=4 and beerfrq4=0 and beerfrqx4=0 and beernum4=98 then wrong=0;
    else if beertotl=5 and beerfrq5=0 and beerfrqx5=0 and beernum5=98 then wrong=0;
    else if beertotl=6 and beerfrq6=0 and beerfrqx6=0 and beernum6=98 then wrong=0;
    else if beertotl=7 and beerfrq7=0 and beerfrqx7=0 and beernum7=98 then wrong=0;
    else if beertotl=8 and beerfrq8=0 and beerfrqx8=0 and beernum8=98 then wrong=0;
    else if beertotl=9 and beerfrq9=0 and beerfrqx9=0 and beernum9=98 then wrong=0;
    else if beertotl=10 and beerfrq10=0 and beerfrqx10=0 and beernum10=98 then wrong=0;
    else if beertotl=11 and beerfrq11=0 and beerfrqx11=0 and beernum11=98 then wrong=0;
    else if beertotl=12 and beerfrq12=0 and beerfrqx12=0 and beernum12=98 then wrong=0;
    else wrong=1;
run;

proc freq data=work.adeno1;
    tables wrong;
run;

You might also benefit from properly indenting your code, as I have done above.

--
Paige Miller

View solution in original post

1 REPLY 1
PaigeMiller
Diamond | Level 26

Your ELSE is not correct. Try this:

 

libname adeno '/home/u58566978/adeno';
/*These next three lines not relevant to this problem, so I have commented them out */
/*data work.adeno1;*/
/*set adeno.finch_gjred;*/
/*run;*/

data work.adeno1;
    set adeno.finch_gjred;
    if beertotl=2 and beerfrq2=0 and beerfrqx2=0 and beernum2=98 then wrong=0;
    else if beertotl=3 and beerfrq3=0 and beerfrqx3=0 and beernum3=98 then wrong=0;
    else if beertotl=4 and beerfrq4=0 and beerfrqx4=0 and beernum4=98 then wrong=0;
    else if beertotl=5 and beerfrq5=0 and beerfrqx5=0 and beernum5=98 then wrong=0;
    else if beertotl=6 and beerfrq6=0 and beerfrqx6=0 and beernum6=98 then wrong=0;
    else if beertotl=7 and beerfrq7=0 and beerfrqx7=0 and beernum7=98 then wrong=0;
    else if beertotl=8 and beerfrq8=0 and beerfrqx8=0 and beernum8=98 then wrong=0;
    else if beertotl=9 and beerfrq9=0 and beerfrqx9=0 and beernum9=98 then wrong=0;
    else if beertotl=10 and beerfrq10=0 and beerfrqx10=0 and beernum10=98 then wrong=0;
    else if beertotl=11 and beerfrq11=0 and beerfrqx11=0 and beernum11=98 then wrong=0;
    else if beertotl=12 and beerfrq12=0 and beerfrqx12=0 and beernum12=98 then wrong=0;
    else wrong=1;
run;

proc freq data=work.adeno1;
    tables wrong;
run;

You might also benefit from properly indenting your code, as I have done above.

--
Paige Miller

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