Hello,
I'm trying to combine 3 columns with four observations into a single column with twelve observations.
If I have data that looks like:
A B C
1 5 9
2 6 10
3 7 11
4 8 12
How would I get it to look like:
D
1
2
3
4
5
6
7
8
9
10
11
12
Thanks!
Does order matter?
Data want;
Set have(rename=a=d)
Have(rename=b=d)
Have(rename=c=d);
Keep d;
Run;
If order doesn't matter use proc transpose.
Now that I look at it more closely it should look like:
A 1
A 2
A 3
A 4
B 5
B 6
.
.
.C 12
Thanks!
Proc transpose and then sort.
Proc transpose data=have out=want;
Run;
Proc sort data=want;
By _name_;
Run;
I'm not getting the output that I'm looking for. I'm getting 3 observations with multiple columns. I would like there to be two columns with 12 observations. I'm not sure what I'm doing wrong here.
data have;
infile 'have.txt';
input A B C;
Proc transpose data=have out=want;
Run;
Proc sort data=want;
By _name_;
Run;
You're correct, proc transpose seems to want an ID, I added a row number to implement this. You could also just transpose using a data step as well if you wanted.
data have;
input A B C;
cards;
1 5 9
2 6 10
3 7 11
4 8 12
;
run;
data want;
set have;
array vars(3) a b c;
do i=1 to dim(vars);
value=vars(i);
name = vname(vars(i));
output;
end;
keep value name;
run;
proc sort data=want;
by name;
run;
Or the Proc Transpose method:
data have;
input A B C;
cards;
1 5 9
2 6 10
3 7 11
4 8 12
;
run;
data have;
set have;
id=_n_;
run;
proc transpose data=have out=want;
by id;
run;
proc sort data=want;
by _name_;
run;
proc print data=want;
run;
I used the proc transpose method and it worked great!
Thank you!
@Reeza's initial idea could have been extended in the following way:
Data want;
length var $8;
Set have(rename=a=d in=ina)
Have(rename=b=d in=inb)
Have(rename=c=d in=inc);
var = choosec(ina+2*inb+3*inc,"A", "B", "C");
Keep var d;
Run;
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