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ziv
Calcite | Level 5 ziv
Calcite | Level 5


I have -
A list of months called "priod" from month 1 to month 360 in varying leaps - sometimes of three months, sometimes half a year, sometimes a year. At the same time there is a column called "b" and accordingly a product price for each such period. These two variables I mentioned are in a table called CHANGE_PERIOD.
Example:

 

priod
1
3
6
12
24
36

60

120.....

until 360

 

b

10
30
30
60

70

90

 

I want-
Create a new column called "New" for those 360 months, where in this column the price changes every month in a linear calculation of what the price would have been if the change had happened every month. Example of what I need:
period_new
1
2
3
4
5
6
7
8
9
10
until 360

 

b
10
20
30
30

30

.............. 360 prices

11 REPLIES 11
ziv
Calcite | Level 5 ziv
Calcite | Level 5

Hi, first of all, thank you very much for your reply.
I did not find a place that explains how to fill in the gaps with a linear change.
In the examples you sent, I saw that they show how to return the previous figure, average, value 0, etc.
Thanks, Ziv

sbxkoenk
SAS Super FREQ

Is this what you want (linear interpolation with method=join in PROC EXPAND)?

data have;
datum='01OCT2022'd; value=0;    output;
datum='01JAN2023'd; value=1000; output;
run;

PROC EXPAND data=have out=want method=join to=month;
 id datum;
 convert value;
run;
/* end of program */

Koen

ziv
Calcite | Level 5 ziv
Calcite | Level 5

I need the missing values to be automatically linear, for example everything between 3 and 6 should be 0.91

 

 

 

 

להשתמש.jpeg

 

 

 

ziv
Calcite | Level 5 ziv
Calcite | Level 5

I need the missing values to be automatically linear, for example everything between 1 and 12 should be 0.91 

 thanks evryone ;

להשתמש.jpeg

sbxkoenk
SAS Super FREQ

You want this ??
I already know the answer , because I have just (5 seconds ago) seen your screenshot.
The answer is NO --> You do NOT want the below , but I am still publishing the program 😉 :

data have;
date='01JAN2022'd; value=1;  output;
date='01DEC2022'd; value=12; output;
run;

proc timedata data=have out=want
              print=(/*scalars*/ arrays);
              id date interval=month acc=t format=yymmdd.;
              vars value;
              outarrays  myvalue;
              *outscalars mystats;

	   do t = 1 to 1;
		myvalue[t] = value[t];
       end;
       do t = 2 to dim(value);
		myvalue[t] = (12-1)/10;
       end;

run;
QUIT;
/* end of program */

Koen

sbxkoenk
SAS Super FREQ

Screenshot made it clear to me.
What you want is the "LAST VALUE CARRIED FORWARD" missing value imputation.
You can look in this communities for LACF or "LAST VALUE CARRIED FORWARD" , you will find many hits.

 

For numeric variables , it's extremely easy.
Just use PROC EXPAND with method=step for missing value interpolation.

 

You need an example?

BR,

Koen

ziv
Calcite | Level 5 ziv
Calcite | Level 5

Actually yes, I would love an example.
I'm new with sas,

thank you very very 🙂

sbxkoenk
SAS Super FREQ

Here you are :

data work.class;
 set sashelp.class;
 datum = _N_;
 if mod(_N_,3) NE 0 then do; weight=.; height=.; end;
run;

PROC EXPAND data=work.class out=work.class_out 
            method=step EXTRAPOLATE from=day to=day;
 id datum;
 convert weight = weight_out ;
 convert height = height_out ;
run;
/* end of program */

Koen

ziv
Calcite | Level 5 ziv
Calcite | Level 5

Thanks, but that's still not what I meant.
In your command between 5-7 he will put the value that was before -5
I want him to apply 6, a linear increase/decrease in this case an increase.

sbxkoenk
SAS Super FREQ

Like this?

( sorry, but it's not clear to me what you want exactly )
     Previous program had method=step.
     Now I changed method=step into method=join.

data work.class;
 set sashelp.class;
 datum = _N_;
 if mod(_N_,3) NE 0 then do; weight=.; height=.; end;
run;

PROC EXPAND data=work.class out=work.class_out 
            method=join EXTRAPOLATE from=day to=day;
 id datum;
 convert weight = weight_out ;
 convert height = height_out ;
run;
/* end of program */

Koen

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