working on dates functionality

[meena_gowtham]

hello,

i have given a code like this 

  data acl;

x=ceil(0.55);

y=floor(1.30);

z=round(1959.896);

d= put(mdy(x,y,z)+365,date9.);

run;

Here I am getting the output with these values:

x=1 y=1 z=1960 z=31dec1960

But why I am getting z value with in the same year even though i have given +365 days so this would result me with the value that is incremented to next year.

Kindly help me if I am missing anything here. 

[Reeza]

Leap years, 1960 is a leap year with 366 days, which is why you get Dec 31st.

  data acl;

x=ceil(0.55);

y=floor(1.30);

z=round(1959.896);

d= put(mdy(x,y,z)+365,date9.);

d2 = intnx('year', mdy(x, y, z), 1, 's');
format d2 date9.;

d3 = d2;
format d3 ddmmyys10.;

run;

Here's a great, but longer and in depth, reference for dates and times in SAS
https://communities.sas.com/t5/SAS-Communities-Library/Working-with-Dates-and-Times-in-SAS-Tutorial/...

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@meena_gowtham wrote:

hello,

i have given a code like this 

  data acl;

x=ceil(0.55);

y=floor(1.30);

z=round(1959.896);

d= put(mdy(x,y,z)+365,date9.);

run;

Here I am getting the output with these values:

x=1 y=1 z=1960 z=31dec1960

But why I am getting z value with in the same year even though i have given +365 days so this would result me with the value that is incremented to next year.

Kindly help me if I am missing anything here. 

---

[Tom]

If you want to increment by a YEAR then tell SAS to do that.

d_string= put(intnx('year',mdy(x,y,z),1,'s'),date9.);