timevalue into numaric

[sathya66]

All,

If I run below code it works majority of time.

But won't work few times

For example, if the

1. TIME = 15:01:50

TIMEVALUE =151.5

 But looking for 1501.50

 2. TIME = 00:00:09

TIMEVALUE = 0.9

Looking for 0000.09

3. TIME = 09:22:09

TIMEVALUE = 922.9

Looking for 0922.09

data WORK.time_test;
    format time time8.;
/*    time = "14:04:46"t;*/
      time=time();
      timevalue = input(strip(hour(time))||strip(minute(time))||strip(.)||strip(round(second(time))),8.2);
  
    put time ;
    put timevalue;
      run;

[BrunoMueller · Accepted solution]

Use the NLTIME function (there is also a NLDATE function). See example program below.

NLTIME returns a char value, this is converted to a numeric and the Z7.2 will print leading zeros

data want;
  do timevalue = "15:01:50"t, "00:00:09"t , "09:22:09"t;
    newTimeValue = nltime(timeValue, '%H%M.%S');
    newTimeValue_n = input(newTimeValue, best8.);
    output;
  end;

  format timevalue tod8. newTimeValue_n z7.2;
run;

[s_lassen]

I would use the TIME. format instead:

data _null_;
  timevalue=time();
  format timevalue time11.2;
  put timevalue=;
run;

The time-value will then display nicely. And you can subtract it from another time-value to get the number of seconds between the two.

If you MUST do it the other way, it would be better to do it like this:

data _null_;                                            
  timevalue=time();                                     
  timevalue=hour(timevalue)*10000+minute(timevalue)*100 
            +second(timevalue);                         
  format timevalue z9.2;                                
  put timevalue=;                                       
run;

[Kurt_Bremser]

Why do you want such a useless number?