All,
If I run below code it works majority of time.
But won't work few times
For example, if the
1. TIME = 15:01:50
TIMEVALUE =151.5
But looking for 1501.50
2. TIME = 00:00:09
TIMEVALUE = 0.9
Looking for 0000.09
3. TIME = 09:22:09
TIMEVALUE = 922.9
Looking for 0922.09
data WORK.time_test;
format time time8.;
/* time = "14:04:46"t;*/
time=time();
timevalue = input(strip(hour(time))||strip(minute(time))||strip(.)||strip(round(second(time))),8.2);
put time ;
put timevalue;
run;
Use the NLTIME function (there is also a NLDATE function). See example program below.
NLTIME returns a char value, this is converted to a numeric and the Z7.2 will print leading zeros
data want;
do timevalue = "15:01:50"t, "00:00:09"t , "09:22:09"t;
newTimeValue = nltime(timeValue, '%H%M.%S');
newTimeValue_n = input(newTimeValue, best8.);
output;
end;
format timevalue tod8. newTimeValue_n z7.2;
run;
Use the NLTIME function (there is also a NLDATE function). See example program below.
NLTIME returns a char value, this is converted to a numeric and the Z7.2 will print leading zeros
data want;
do timevalue = "15:01:50"t, "00:00:09"t , "09:22:09"t;
newTimeValue = nltime(timeValue, '%H%M.%S');
newTimeValue_n = input(newTimeValue, best8.);
output;
end;
format timevalue tod8. newTimeValue_n z7.2;
run;
I would use the TIME. format instead:
data _null_;
timevalue=time();
format timevalue time11.2;
put timevalue=;
run;
The time-value will then display nicely. And you can subtract it from another time-value to get the number of seconds between the two.
If you MUST do it the other way, it would be better to do it like this:
data _null_;
timevalue=time();
timevalue=hour(timevalue)*10000+minute(timevalue)*100
+second(timevalue);
format timevalue z9.2;
put timevalue=;
run;
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