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lillymaginta
Lapis Lazuli | Level 10

Hi all,

I have the following statement:

 

data a (drop=i); set b; array x{*} dx:; r=1=0;

do i=1 to dim(x); if susbtrn(x{i},1,3) in ('210','220') then do; r=1;

leave;

end;

end;

run;

 

my question if I want to include another entry with a length of 4 meaning if susbtrn= '210', '220', '2320', how can I adjust the above statement to account for different the lengths?

 

1 ACCEPTED SOLUTION

Accepted Solutions
novinosrin
Tourmaline | Level 20

data a (drop=i); set b; array x{*} dx:; r=1=0;

do i=1 to dim(x);
if susbtrn(x{i},1,3) in ('210','220')
or susbtrn(x{i},1,4) in ( '2320')
then do; r=1;

leave;

end;

end;

run

View solution in original post

2 REPLIES 2
novinosrin
Tourmaline | Level 20

data a (drop=i); set b; array x{*} dx:; r=1=0;

do i=1 to dim(x);
if susbtrn(x{i},1,3) in ('210','220')
or susbtrn(x{i},1,4) in ( '2320')
then do; r=1;

leave;

end;

end;

run

Astounding
PROC Star

I'm not sure you have the spelling right, but here's a variation that works for character strings:

 

if x{i} in : ('210','220','2299') then do;

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