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Riteshdell
Quartz | Level 8

Hello Expert,

 

I need a small Doubt, I am running a do macro loop for 72 columns, means 12 categories.

 

I have 6 columns which attribute name is repeating with increment numbers like below.

 

Base1,tax1,com1,int1,amt1,charges1,Base2,tax2,com2,int2,amt2,charges2,Base12,tax12,com12,int12,amt12,charges12.

 

I am generating only 3 column value (base,tax,int) in one column row wise.

 

%var1=base;

%var2=tax;

%var3=com;

%var4=int;

%var5=amt;

%var6=charges;

 

%do base=1 %to 12;

%do i=1 %to 4;

 

 

so I am generating a value in one column which will take data all 4 columns.

Now my question is to leave third column value only to take 1,2,4 value of i.

 

how can we can skip one value in do macro loop.

 

Please help  me.

 

2 REPLIES 2
Astounding
PROC Star

An easy patch:

 

%do base=1 %to 12;

%do i=1 %to 4;

%if &i ne 3 %then %do;

 

Macro language does not support iterating through a list of values, only iterating over a range.

 

Another possibility:

 

%if &i=3 %then %let i=4;

RW9
Diamond | Level 26 RW9
Diamond | Level 26

And why the need for macro?  

data want;
  set have;
  array base_a{*} base:;
  array tax_a{*} tax:;
  ...
  do i=1 to dim(base_a);
    ...
  end;
run;

There are of course various other options as well.  Restructure the data for one:

ROW_ID  BASE  TAX  ...
1              xx        xx    ...
2              xx        xx    ...
etc.

Then yu just apply any calculations to base or tax on a row level rather than iterating across.  Simpler coding, and if you need a report at the end with it across the page, then do a transpose the data.

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