Hi,
I'd like to replace values of a list of similar variables (replace 'C' with '2') for 12 variables:
data want;
set dat;
if var01 = 'C' then var01 = '2';
if var02 = 'C' then var02 = '2';
if var03 = 'C' then var03 = '2';
...
if var12 = 'C' then var12 = '2';
run;
How can I simplify this code with macro/loop? I tried the following codes but did not work:
%let var_list = var01-var12;
%macro loop(var_list);
%local i next_var;
data want;
set dat;
%do i = 1 %to %sysfunc(countw(&var_list));
%let next_name = %scan(&var_list, &i);
if &next_var = 'C' then &next_var = '2';
%end;
run;
%mend;
%loop(&var_list);
Any idea? Thanks!
No macro needed. Use an ARRAY.
data want;
set dat;
array v var01-var12;
do i=1 to dim(v);
if v(i)='C' then v(i)='2';
end;
drop i;
run;
No macro needed. Use an ARRAY.
data want;
set dat;
array v var01-var12;
do i=1 to dim(v);
if v(i)='C' then v(i)='2';
end;
drop i;
run;
Build your skills. Make connections. Enjoy creative freedom. Maybe change the world. Registration is now open through August 30th. Visit the SAS Hackathon homepage.
Register today!Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Select SAS Training centers are offering in-person courses. View upcoming courses for: