regulare expression; detecte the special charatere '('

[mansour_ib_sas]

Hello;

I'm trying to extract whith regulars expressions the parts of names that are surrounded by paratheses.

For started, I try to detect what starts with a parenthesis and no word does match.

That is why, i am asking you for help me.

Thank you

data test;
  input name $25.;
  cards;
test (ex)
(ex) test
test test
;
run;


data test1;
set test;
i=1;
do while (scan(name,i, " ") ne ' ') ;
    part=scan(name,i);
    regex = prxparse("/(?<=\()/");
    if prxmatch(regex, part) >0 then output;
    i+1;
end;
run;

[PeterClemmensen]

So for each value of the name variable that is inside a parenthesis, you want a new record, correct? 

From your posted data set, what does your desired result look like?

[mansour_ib_sas]

Thank you for your answer,

For your first question, i want to delete the reccord inside a parenthesis  by regulare expression.

For your second question:

data test;
  input name $25.;
  cards;

test
test
test test;
run;

[PeterClemmensen · Accepted solution]

Ok. You can do something like this

data test;
  input name $25.;
  cards;
test (ex)
(ex) test
test test
;
run;

data want;
   set test;
   a=prxchange('s/\(.*\)//', -1, name);
run;

[PGStats]

Or rather,

data test;
  input name $25.;
  cards;
test (ex)
(ex) test
(ex) test (ex)
test test
;

data want;
   set test;
   new_name = prxchange('s/\s*\(.*?\)\s*//', -1, name);
run;

[mansour_ib_sas]

To the method I'm trying to applay, I understood where the problem came.

At the scan, I forgot  to add space as a separator.

Now, I can separate the string charcters correctly.

Thank you for you help.

data test1;
set test;
i=1;
do while (scan(name,i, " ") ne ' ') ;
    part=scan(name,i,'');
    regex = prxparse('/\(/');
    if prxmatch(regex, part) >0 then output;
    i+1;
end;
run;