Given the SAS data set SASDATA TWO:
SASDATA TWO
XY
----
52
31
56
The following SAS program is submitted:
data sasuser.one two sasdata.three;
set sasdata two;
if x = 5 then output sasuser.one;
else output sasdata two;
run;
What is the result?
Not sure why the answer is
A. data set SASUSER.ONE has 5 observations
data set SASUSER.TWO has 5 observations
data set WORK.OTHER has 3 observations
Thanks!
AS written this line:
set sasdata two;
indicates that you are combining two different data sets Sasdata AND two, which by default would both be in the WORK library.
Your code does not actually show a reference to SASUSER.TWO or Other.
The periods in the data set names are crucial to accurate code as the . separates the library name, the bit before the . which is a storage location and the actual dataset name, the bit after the period.
Your question is not coherent. There is no dataset "other" mentioned in the datastep at all.
STRONG HINT:
run examples yourself to make sure that you present working code here, this is more or less a bad joke.
AS written this line:
set sasdata two;
indicates that you are combining two different data sets Sasdata AND two, which by default would both be in the WORK library.
Your code does not actually show a reference to SASUSER.TWO or Other.
The periods in the data set names are crucial to accurate code as the . separates the library name, the bit before the . which is a storage location and the actual dataset name, the bit after the period.
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