Hi...I have a dataset that I want to select only or identify those customers as repaet customers by their ID. I can obtain a partial dataset by using the lag function but the very first record of each customer who is a repeat customer does not have "Yes" as the correct entry. Any suggestions how I might be able include the first time that repeat customer ID is found...Thanks.
Have:
| ID | DATE | SALES |
| 1223 | 2016-01-23 | 73.55 |
| 1445 | 2016-01-12 | 88.45 |
| 1445 | 2016-02-11 | 54.70 |
| 1445 | 2016-03-10 | 66.15 |
| 1733 | 2016-02-08 | 34.50 |
| 1649 | 2016-02-27 | 66.30 |
| 1649 | 2016-03-13 | 88.20 |
Want:
| ID | Date | Sales | Repeat |
| 1223 | 2016-01-23 | 73.55 | |
| 1445 | 2016-01-12 | 88.45 | Yes |
| 1445 | 2016-02-11 | 54.70 | Yes |
| 1445 | 2016-03-10 | 66.15 | Yes |
| 1733 | 2016-02-08 | 34.50 | |
| 1649 | 2016-02-27 | 66.30 | Yes |
| 1649 | 2016-03-13 | 88.20 | Yes |
Use the By groups?
data want;
set have;
BY ID;
if not first.ID then repeat='Yes';
run;
EDIT: Sorry, it looks like you want to identify all records that aren't unique. You can do this using First/Last, where not first.ID and last.iD
data want;
set have;
BY ID;
if not (first.ID and last.ID) then repeat='Yes';
run;
Use the By groups?
data want;
set have;
BY ID;
if not first.ID then repeat='Yes';
run;
EDIT: Sorry, it looks like you want to identify all records that aren't unique. You can do this using First/Last, where not first.ID and last.iD
data want;
set have;
BY ID;
if not (first.ID and last.ID) then repeat='Yes';
run;
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.