data input;
input ID $ period amt;
cards;
X 201001 10000
X 201004 800
X 201006 200
Y 201101 100
Y 201102 100
Z 201201 .
Z 201202 .
Z 201203 .
;
run;
Assuming that I understand what you want, here's one way:
data defaults;
set test1 (keep=id amt);
by id;
where amt > .;
if first.id;
rename amt=default_amt;
run;
data want;
merge test1 defaults;
by id;
if amt > . then default_amt = amt;
else amt = default_amt;
drop default_amt;
run;
It's untested, but looks like it should work just fine.
Please repost your orginial question or a close version.
Without the question the response makes no sense.
data input; input ID $ period amt; cards; X 201001 10000 X 201004 800 X 201006 200 Y 201101 100 Y 201102 100 Z 201201 . Z 201202 . Z 201203 . ; run; data want; merge input input(keep=id period rename=(id=_id period=_period) firstobs=2); output; if id=_id then do; do i=period+1 to _period-1; period=i;output; end; end; drop _: i; run;
April 27 – 30 | Gaylord Texan | Grapevine, Texas
Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and save with the early bird rate—just $795!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.