last word from right

[podarum]

 Hi,  I'm trying to find if there is a space after the last 3 digits then it's a canadian address otherwise it's US.

field

23 Yonge st.  M4H 6F7

23 Yonge st. 902910

827 Bla Bla Rd. T7G 7K2

Sammy Rd. 38278

where there is a postal code I'd say Canadian and 2 and 4 are US.. So I figured if there is a space after the last 3 digits from the right then it's  Can, otherwise US.

Thnks

[Jagadishkatam · Accepted solution]

Please try perl as below

data want;
set have;
if prxmatch('m/\s\d\w\d$/',strip(field)) then flag='Can';
else flag='US';
run;

[ChrisNZ]

You could use variations of:

if length(scan(ADDRESS,-1)) in (3,6) then COUNTRY='CANADA';

[Reeza]

A different option

1. Use COUNTW to determine the number of words

2. Find last word

3. If Length = 5 then it's US, otherwise, it's CAN.

The Perl is more efficient though

length country $8.;

n_words = countw(text);
last_word = scan(text, n_words);

if length(last_word)=3 then country = 'CAN';
else if length(last_word)=5 then country='US';
else country='CHECKME';

[kiranv_]

something like this

data want;
set have;
if prxmatch("m/\s.{3}$/oi",trim(addr_ln_1))> 0 then cntry='CAN';
else cntry='US';
run;