intck with timestamp

[BrahmanandaRao]

dm 'log;clear;odsresults;clear';

data d;
start_date='18Nov2014'd ;
format start_date date9.;
current_date='18Nov2020'd ;
format current_date date9.;
years=intck('Year' ,start_date,current_date);
months=intck('Month',start_date,current_date);
days= intck('Day',start_date,current_date);
hours=intck('hour','22:10:00't ,1)	;
proc print;run;

Here I want to get hour minute second from start_date and current_date why it gives 22 hours

[Kurt_Bremser]

'hour' is a time interval, times are counts of seconds. 1 translates to 00:00:01, so you have 22 hour boundaries between that and 22:10:00.

If you want the difference between dates (there are no timestamp/datetime values in your code) expressed as hours, multiply the day difference by 24.