if then do else then do

[BrahmanandaRao]

data ds;
set sashelp.class ;
if age=11 then do;
   ages1='Minor';
   else if age= ' ' then ages1='--';
   end;
if age>11 then do;
ages2='Major';
else if age=' ' then ages2='--';
end;

proc print noobs;
run;   

Required Output:

Name	Sex	Age	Height	Weight	ages1	ages2
Alfred	M	14	69	112.5	--	Major
Alice	F	13	56.5	84	--	Major
Barbara	F	13	65.3	98	--	Major
Carol	F	14	62.8	102.5	--	Major
Henry	M	14	63.5	102.5	--	Major
James	M	12	57.3	83	--	Major
Jane	F	12	59.8	84.5	--	Major
Janet	F	15	62.5	112.5	--	Major
Jeffrey	M	13	62.5	84	--	Major
John	M	12	59	99.5	--	Major
Joyce	F	11	51.3	50.5	Minor	--
Judy	F	14	64.3	90	--	Major
Louise	F	12	56.3	77	--	Major
Mary	F	15	66.5	112	--	Major
Philip	M	16	72	150	--	Major
Robert	M	12	64.8	128	--	Major
Ronald	M	15	67	133	--	Major
Thomas	M	11	57.5	85	Minor	--
William	M	15	66.5	112	--	Major

[Tom · Accepted solution]

Is there a question you want to ask?

Do you want us to guess what the question might be?

Why do you treat AGE as NUMERIC in the first place you mention it.  But then treat it as CHARACTER the second place you mention it?

Which type of variable is AGE?  Numeric or character?

And why would you test AGE a second time within the DO/END block that can only be entered when AGE is 11 ?  You already know that the value of AGE is 11 or it would never have gotten to that second test.

It looks like you only need to test age ONCE since you only have two different outputs.

data want;
  set sashelp.class;
  length ages1 ages2 $5 ;
  if age = 11 then do;
    ages1='Minor';
    ages2='--';
  end;
  else do;
    ages2='Major';
    ages1='--';
  end;
run;

[Srinivas_Naren]

Instead of creating two variables we can perform with one 

data edit;
set sashelp.class;
if age >= 15 then do;
applied='Major';
end;
else if age<15 then do;
applied='Minor';
end;
run;
proc print data = edit;
run;