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vraj1
Quartz | Level 8

i want to assign values for EXD based on the below condition

EXT is "pine", EXD should be assigned by value 2 for the first 2 days, value 4 for the next 2 days and value 6 for the remaining Period A. If EXT is "ozi", EXD should be assigned by value 5 for the first 2 days, value 10 for the next 2 days and value 15 for the remaining Period A.

 

Attached test data. can any one suggest how to do it.?

1 ACCEPTED SOLUTION

Accepted Solutions
FreelanceReinh
Jade | Level 19

Hi @vraj1,

 

There are at least two possible interpretations of your criteria and hence different solutions:

 

  1. The "first 2 days" are days 1 and 2 (according to variable DAY), the "next 2 days" are days 3 and 4 and so on.
    data want;
    set test(drop=exd);
    if period='A' then do;
           if ext='pine' then exd=2*min(int((day+1)/2),3);
      else if ext='ozi'  then exd=5*min(int((day+1)/2),3);
    end;
    run;
  2. The "first 2 days" with EXT='pine' correspond to the first two observations with PERIOD='A' and EXT='pine' within an ID regardless of DAY (but assuming chronological sort order), etc.
    data want;
    set test(drop=exd);
    by id day;
    if first.id then call missing(_cp, _co);
    if period='A' then do;
           if ext='pine' then do; _cp+1; exd=2*min(int((_cp+1)/2),3); end;
      else if ext='ozi'  then do; _co+1; exd=5*min(int((_co+1)/2),3); end;
    end;                                     
    drop _:;
    run;

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1 REPLY 1
FreelanceReinh
Jade | Level 19

Hi @vraj1,

 

There are at least two possible interpretations of your criteria and hence different solutions:

 

  1. The "first 2 days" are days 1 and 2 (according to variable DAY), the "next 2 days" are days 3 and 4 and so on.
    data want;
    set test(drop=exd);
    if period='A' then do;
           if ext='pine' then exd=2*min(int((day+1)/2),3);
      else if ext='ozi'  then exd=5*min(int((day+1)/2),3);
    end;
    run;
  2. The "first 2 days" with EXT='pine' correspond to the first two observations with PERIOD='A' and EXT='pine' within an ID regardless of DAY (but assuming chronological sort order), etc.
    data want;
    set test(drop=exd);
    by id day;
    if first.id then call missing(_cp, _co);
    if period='A' then do;
           if ext='pine' then do; _cp+1; exd=2*min(int((_cp+1)/2),3); end;
      else if ext='ozi'  then do; _co+1; exd=5*min(int((_co+1)/2),3); end;
    end;                                     
    drop _:;
    run;

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