BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Amy0223
Quartz | Level 8

Hi community,

I don't know how to code this problem below.  Any help is much appreciated!

 

Variable name fullname (length $30) has a respondent's first, middle, and last name. Create var shortname (length $20), which has only the first and last name, separated by a single blank.

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

You can use the LENGTH keyword in SQL to tell SAS how many bytes to use when storing the variable.

.... as shortname length=20

You could also have used the SUBSTR() function and SAS would have figured out that your expression could only return 20 bytes.

substr(....,1,20) as shortname

View solution in original post

6 REPLIES 6
PaigeMiller
Diamond | Level 26

The SCAN() function ought to work here.

 

For example

 

SCAN(fullname,1) extracts the first "word" from fullname

 

Give it a try, see if you can get it to do what you want.

--
Paige Miller
Amy0223
Quartz | Level 8

I tried it with sql and prxChange. It seems to work but I don't know how to specify length $20 for shortName.

data a;
input fullname $30.;
cards;
George W. Bush
George W Bush
George Bush
;
run;

proc sql;
select fullname, 
    prxChange("s/(\w+\s)(\s*\w\.?\s+)(\w+)/\1\3/io",1,fullname) as shortName
from a;
quit;
Tom
Super User Tom
Super User

You can use the LENGTH keyword in SQL to tell SAS how many bytes to use when storing the variable.

.... as shortname length=20

You could also have used the SUBSTR() function and SAS would have figured out that your expression could only return 20 bytes.

substr(....,1,20) as shortname
Amy0223
Quartz | Level 8
Thank you very much for your kind help! I really appreciate it!
Astounding
PROC Star

Tom, does SUBSTR actually use the length of $20?  Admittedly it has been a long time since I tested this, but I recall that SUBSTR used the length of the incoming string to define a newly created variable.  The basic idea was that the third parameter could be an expression instead of a hard-coded value, and so might not be capable of setting a length.

Tom
Super User Tom
Super User

In a data step it will guess the length based on the input to the SUBSTR() function. But in SQL it will guess the length based on the output of the SUBSTR() function.

data x;
  x=substr('1234567890',1,6);
  y=vlength(x);
  put y=;
run;

proc sql;
 create table test1 as select  substr('1234567890',1,6) as x from sashelp.class(obs=1);
quit;
data _null_;
 set test1;
 y=vlength(x);
 put y=;
run;

SAS Innovate 2025: Call for Content

Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!

Submit your idea!

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 6 replies
  • 1076 views
  • 1 like
  • 4 in conversation