BookmarkSubscribeRSS Feed
sasprogramming
Quartz | Level 8

I am using the following code to find the word DI. The code below returns true when it looks at "CREDIT". However I want it to return false, DI is in CREDIT, but I only want cases true when DI is a word. How do i achieve this?

 

if findw(field_to_search_from, 'DI') ge 1 then flag= 1;
6 REPLIES 6
jimbarbour
Meteorite | Level 14

I would use the FIND or FINDW functions to identify distinct words.

 

For example: 

DATA	_NULL_;
					*----+----1----+----2----+----3----+----4----+----5-;
	String		=	'In Army boot camp, the DI is in charge.';

	Position	=	FINDW(String, 'DI');

	PUTLOG  "The position is " Position 2.;
RUN;

 Yields:

The position is 24

 

Jim

andreas_lds
Jade | Level 19

Please post the code you have including data in usable form (data step with datalines, no attachments).

Using findw is the right choice.

Josie1
Obsidian | Level 7

try putting a space before and after like ' DI '

sasprogramming
Quartz | Level 8

But if CREDIT is the first word in the field_to_search_from then it wont have a space before it?

Josie1
Obsidian | Level 7

not unless you write CRE DI T

andreas_lds
Jade | Level 19

@Josie1 wrote:

try putting a space before and after like ' DI '


Not necessary if findw is used.

hackathon24-white-horiz.png

2025 SAS Hackathon: There is still time!

Good news: We've extended SAS Hackathon registration until Sept. 12, so you still have time to be part of our biggest event yet – our five-year anniversary!

Register Now

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 6 replies
  • 1906 views
  • 1 like
  • 4 in conversation