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Riteshdell
Quartz | Level 8

hello experts,

 

I need a help to solve a query. I have a dataset and column called NAME but this column Name has some kind of encoding data like .

 

I want to check which row has encoding data of ASC value which is falling between 161 to 255.

Suppose if you below code and data , so it should check each observation each string and identify the each string ASC value  and if any ASC value in observation is falling between 161 to 255, then a new column RANK_VALUE should give result of ASC Value,

if no value from 161 to 255, then null should pass.

 

data test;
input name $32.;
datalines;
RÃm
John
èra
©kumara
¶cris
;
run;
output :


Name   Rank_value

RÃm       195
John
èra       232
©kumara    169
¶cris       182
3 REPLIES 3
Riteshdell
Quartz | Level 8
rank procedure I ahev idea, but here each string we need to check . with array and loop we need to find out
RW9
Diamond | Level 26 RW9
Diamond | Level 26

Random words, ahve no idea.

 

Functions work anywhere in arrays, or loops, anywhere in datastep.  Provide test data in the form of a datastep, show what the output should look like, explain the logic between the two.

data test;
  input name $32.;
  do i=1 to lengthn(name);
    rank_value=rank(char(name,i));
    output;
  end;
datalines;
RÃm
John
èra
©kumara
¶cris
;
run;

That might not actually do what you want however, try it out.  Some other possiblities:

http://www.sascommunity.org/planet/blog/category/rank/

29May example, shows compress removing specials, but you could reverse it with:

data want;
  set have;
  if lengthn(compress(name," ","ad"))>0 then result="special character";
run;

So remove the alaph and numerics then if the lengthn is greater than 0 you know you have odd characters.

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