data test;
do year = 1 to 5;
do month = 1 to 12;
x+1;
output;
end;
end;
run;
can somebody explain how this nested loop works , how I m getting 60 observations in output ?
see the below link, it clearly explains about nesting loops.
Break it down:
do year = 1 to 5; < - do this code 5 times
do month = 1 to 12;
x+1;
output;
end;
end;
For each of those five times:
do month = 1 to 12; <- do this code 12 times
x+1;
output;
Thus you are running 12 times (inner loop) for each of the 5 times (outer loop) = 60 iterations.
@sanyam13 A quick way to grasp the way my professor taught me a loop construct in any programming language
1. inner most look executes in full and followed by one by one to reverse top order
2. total number of loops processed = stopvalue1*stopvalue2*stopvalueN= 5*12=60 in your case
@novinosrin wrote:
2. total number of loops processed = stopvalue1*stopvalue2*stopvalueN= 5*12=60 in your case
@sanyam13: It goes without saying that "stop value" in the above calculation does not always equal the value following the TO keyword (such as 10 in do i=1 to 10), but can differ from that value in many ways depending on start value (do i=0 to 10), increment (do i=1 to 10 by 2), WHILE/UNTIL conditions, the code performed in the loop (e.g. LEAVE statement), etc.
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