BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Georg_UPB
Fluorite | Level 6

Hi everyone,

In the example below it makes a difference whether a macro variable is defined using CALL SYMPUT (here: &ab.) or %LET (here: &ab2.).

Why is that and are there any other noteworthy differences?

Thanks!

%Let a=1;

%Let b=2;

Data _null_;

     Call Symput ('ab','%Eval(&a.+&b.)');

Run;

%Let ab2=%Eval(&a.+&b.);

%Put &ab.;

%Put &ab2.;

%Let b=0;

%Put &ab.;

%Put &ab2.;

1 ACCEPTED SOLUTION

Accepted Solutions
Jagadishkatam
Amethyst | Level 16

Please refer to the below link, it has good information about the question you asked

http://support.sas.com/resources/papers/proceedings10/028-2010.pdf

Thanks,

Jagadish

Thanks,
Jag

View solution in original post

3 REPLIES 3
Jagadishkatam
Amethyst | Level 16

Please refer to the below link, it has good information about the question you asked

http://support.sas.com/resources/papers/proceedings10/028-2010.pdf

Thanks,

Jagadish

Thanks,
Jag
data_null__
Jade | Level 19

It's the VALUE.  They are not the same.  Add this to see the value.

%Put &ab. %superq(ab);

%Put &ab2. %superq(ab2);
Georg_UPB
Fluorite | Level 6

Thank you very much!

hackathon24-white-horiz.png

2025 SAS Hackathon: There is still time!

Good news: We've extended SAS Hackathon registration until Sept. 12, so you still have time to be part of our biggest event yet – our five-year anniversary!

Register Now

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 3 replies
  • 6174 views
  • 4 likes
  • 3 in conversation