BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
sasphd
Lapis Lazuli | Level 10

Hello I want to make the difference between dates by id 

 

data diff;

set JOINT;
days_between = intck('days',Ann_date,lag(Ann_date));
by number;
run;

this program give this 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06 4711
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11 638
46 2009-01-19 2030
53 2008-07-15 188
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267

I want 

 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06  
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11  
46 2009-01-19 2030
53 2008-07-15  
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267
1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User

Assuming 46 is a typo as there's only one record.

 

data diff;

set JOINT;
by Number;

days_between = intck('days',Ann_date,lag(Ann_date));

if first.Number then call missing(days_between);

run;

@sasphd wrote:

Hello I want to make the difference between dates by id 

 

data diff;

set JOINT;
days_between = intck('days',Ann_date,lag(Ann_date));
by number;
run;

this program give this 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06 4711
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11 638
46 2009-01-19 2030
53 2008-07-15 188
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267

I want 

 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06  
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11  
46 2009-01-19 2030????
53 2008-07-15  
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267

 

View solution in original post

2 REPLIES 2
Reeza
Super User

Assuming 46 is a typo as there's only one record.

 

data diff;

set JOINT;
by Number;

days_between = intck('days',Ann_date,lag(Ann_date));

if first.Number then call missing(days_between);

run;

@sasphd wrote:

Hello I want to make the difference between dates by id 

 

data diff;

set JOINT;
days_between = intck('days',Ann_date,lag(Ann_date));
by number;
run;

this program give this 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06 4711
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11 638
46 2009-01-19 2030
53 2008-07-15 188
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267

I want 

 

Number Ann_date days_between
21 2008-11-12  
21 2011-03-29 -867
21 2015-01-21 -1394
21 2016-03-29 -433
24 2003-05-06  
24 2016-01-25 -4647
24 2016-05-10 -106
26 2014-08-11  
46 2009-01-19 2030????
53 2008-07-15  
53 2009-07-27 -377
53 2010-06-11 -319
53 2010-07-16 -35
53 2015-01-15 -1644
53 2015-10-09 -267

 

sasphd
Lapis Lazuli | Level 10

yes it is a typo

thanks

sas-innovate-white.png

Missed SAS Innovate in Orlando?

Catch the best of SAS Innovate 2025 — anytime, anywhere. Stream powerful keynotes, real-world demos, and game-changing insights from the world’s leading data and AI minds.

 

Register now

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 2 replies
  • 2439 views
  • 1 like
  • 2 in conversation