date manupulation

[desireatem]

Hello-,

I have a date format below. I want to drop the last four digit ie 1950 and 1421 from the date and subtract 2/10/2017-2/9/2017

  data AA;

input  ADT_IN  ADT_OUT;

2/9/2017 1950	2/10/2017 1421
2/8/2017 1750	2/10/2017 1240
2/7/2017 1143	2/9/2017 1250
2/8/2017 1256	2/11/2017 0042
2/8/2017 1357	2/9/2017 1339
2/8/2017 1236	2/10/2017 1809
2/8/2017 1236	2/10/2017 1809

;

How do I perform length of stay (LOS) using the above data.  LOS= out-in above

[Reeza]

SCAN to separate components

INPUT to convert character to date

[desireatem]

I do not understand.

[subobscure]

1. scan the date using spaces as delimiter
2. Convert the date to numeric
3. Subtract one value from the other
   
   

data a;
date1="2/9/2017 1950";
date2="2/10/2017 1421";

diff=input(scan(date2,1," "),ddmmyy10.)-input(scan(date1,1," "),ddmmyy10.);
run;

[desireatem]

I did not work.

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;

[Kurt_Bremser]

Post your example dataset (in a data step!), so we can see the content and attributes of your variables.

"It did not work" is about as helpful as "a bicycle tipped over in Beijing". So post the log of your code, and how the result (if there was one) differed from your expectations.

---

@desireatem wrote:

I did not work.

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;

---

[desireatem]

Thank you

[desireatem · Accepted solution]

works

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.)/365;
run;

[subobscure]

Good that I could be of help.
I concur with what @Kurt_Bremser said. If a piece of code is not working for you, you are supposed to give the snapshot of your log