id rx start_date days_supply
1 a 1/1/2005 90
2 b 2/2/2004 60
Hi all, I have the above dataset, I want to divide the periods that the patient can take drug were days supply represent the days the patients taked the drug. For simplicity, if the patient have 90 days means patient takes the drug for 3 months. 60 for two months and so on. Here is the output I am looking for
id rx start_date days_supply
1 a 1/1/2005 30
1 a 2/1/2005 30
1 a 3/1/2005 30
2 b 2/2/2004 30
2 b 3/2/2004 30
data have;
infile datalines;
input id rx $ start_date mmddyy10. days_supply;
format start_date mmddyy10.;
datalines;
1 a 01/01/2005 90
2 b 02/02/2004 60
; run;
data want;
set have;
months = int(days_supply/30);
supply=30;
do i=1 to months;
date = intnx('month',start_date,i-1,'s');
output;
end;
KEEP ID RX supply date;
format date mmddyy10.;
run;
data have;
infile datalines;
input id rx start_date mmddyy10. days_supply;
format start_date mmddyy10.;
datalines;
1 a 01/01/2005 90
2 b 02/02/2004 60
; run;
data want;
set have;
months = days_supply / 30; /* or ceil(days_supply/30) */
start_date_in = start_date;
do i=1 to months;
start_date = intnx('MONth', start_date_in, i-1) + day(start_date_in) -1;
days_supply = 30;
output;
end;
run;
data have;
infile datalines;
input id rx $ start_date mmddyy10. days_supply;
format start_date mmddyy10.;
datalines;
1 a 01/01/2005 90
2 b 02/02/2004 60
; run;
data want;
set have;
months = int(days_supply/30);
supply=30;
do i=1 to months;
date = intnx('month',start_date,i-1,'s');
output;
end;
KEEP ID RX supply date;
format date mmddyy10.;
run;
Thank you!
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