ssn pin ids1 p1 c1as1 p2 c1bs1 c1c
s2 c2s2 c2a
s3 c3s3 c3a
s4 c4as4 p4 c4b
count where pin is missing with pin present for other records : 2 (ssn s1 and s4)
count where pin is not present all : 2 (s2 and s3 )
proc sql;
select sum(all_miss) as all_miss,
sum(miss_count) as miss_count
from
(select count(pin) eq 0 as all_miss,
count(pin) gt 0 as miss_count
from have
group by ssn
having nmiss(pin) gt 0)
;
quit;
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