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radha009
Quartz | Level 8

my table date as date in format 10JUN2018:10:08:40.216 expecting 06-10-2018.

 

Thank you

1 ACCEPTED SOLUTION

Accepted Solutions
novinosrin
Tourmaline | Level 20
data w;
date='10JUN2018:10:08:40.216';
new_date=datepart(input(date, datetime20.));
format new_date mmddyyd10.;
run;

 

Applying this for '-'

 

mmddyyd10

 

View solution in original post

3 REPLIES 3
novinosrin
Tourmaline | Level 20
data w;
date='10JUN2018:10:08:40.216';
new_date=datepart(input(date, datetime20.));
format new_date mmddyy10.;
run;
novinosrin
Tourmaline | Level 20
data w;
date='10JUN2018:10:08:40.216';
new_date=datepart(input(date, datetime20.));
format new_date mmddyyd10.;
run;

 

Applying this for '-'

 

mmddyyd10

 

ballardw
Super User

Or if the existing variable is consistent you can read with the DATE9. informat:

data example;
   date='10JUN2018:10:08:40.216';
   newdate= input(date,date9.);
   format newdate mmddyyd10.;
run;

The informat will only read the first 9 characters.

 

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