data _null_;
call symputx('td','01May2017'd);
call symputx('td1','03May2017'd);
call symputx('td2','15May2017'd);
call symputx('td3','10May2017'd);
run;
%put &td. &td1. &td2.;
%macro test;
%if &td1. <= &td. <= &td2. %then %do;
proc print data=sashelp.air;
run;
%end;
%else %do;
proc print data=sashelp.cars; run;
%end;
%mend test;
%test;
In this example, td is not between td1 and td2. Sashelp.air is printed as output. What is the explanation for this?
Thank you.
A set of comparisons works differently in macro language:
%if &td1. <= &td. <= &td2. %then %do;
In macro language, these function as if you had added parentheses:
%if (&td1. <= &td.) <= &td2. %then %do;
The first comparison returns a 1 (if true) or a 0 (if false). You need to spell them out separately:
%if &td1. <= &td. and &td. <= &td2. %then %do;
A set of comparisons works differently in macro language:
%if &td1. <= &td. <= &td2. %then %do;
In macro language, these function as if you had added parentheses:
%if (&td1. <= &td.) <= &td2. %then %do;
The first comparison returns a 1 (if true) or a 0 (if false). You need to spell them out separately:
%if &td1. <= &td. and &td. <= &td2. %then %do;
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.