Hi,
I have an input data as follows.
ID | Flag | date |
1 | 1 | 1.2014 |
1 | 0 | 2.2014 |
1 | 0 | 3.2014 |
1 | 1 | 4.2014 |
1 | 0 | 5.2014 |
1 | 0 | 6.2014 |
1 | 1 | 7.2014 |
1 | 0 | 8.2014 |
1 | 0 | 9.2014 |
1 | 0 | 10.2014 |
2 | 1 | 2.2014 |
2 | 0 | 3.2014 |
2 | 0 | 4.2014 |
2 | 1 | 5.2014 |
2 | 0 | 6.2014 |
2 | 0 | 7.2014 |
2 | 1 | 8.2014 |
2 | 0 | 9.2014 |
I need output as follows.
ID | Flag | date | relative_month1 | relative_month2 | relative_month3 |
1 | 1 | 1.2014 | m1 | ||
1 | 0 | 2.2014 | m2 | ||
1 | 0 | 3.2014 | m3 | ||
1 | 1 | 4.2014 | m4 | m1 | |
1 | 0 | 5.2014 | m5 | m2 | |
1 | 0 | 6.2014 | m6 | m3 | |
1 | 1 | 7.2014 | m7 | m4 | m1 |
1 | 0 | 8.2014 | m8 | m5 | m2 |
1 | 0 | 9.2014 | m9 | m6 | m3 |
1 | 0 | 10.2014 | m10 | m7 | m4 |
2 | 1 | 2.2014 | m1 | ||
2 | 0 | 3.2014 | m2 | ||
2 | 0 | 4.2014 | m3 | ||
2 | 1 | 5.2014 | m4 | m1 | |
2 | 0 | 6.2014 | m5 | m2 | |
2 | 0 | 7.2014 | m6 | m3 | |
2 | 1 | 8.2014 | m7 | m4 | m1 |
2 | 0 | 9.2014 | m8 | m5 | m2 |
for each ID with change in flag number to 1, I want to create a new varibale (relative month variable) and assign it to m1 and the follow up period should increment by 1. Hope the question is clear.
Any help is appreciated. Thanks alot in Advance.
data have;
infile datalines dlm=' ' truncover;
input ID Flag date : $20.;
datalines;
1 1 1.2014
1 0 2.2014
1 0 3.2014
1 1 4.2014
1 0 5.2014
1 0 6.2014
1 1 7.2014
1 0 8.2014
1 0 9.2014
1 0 10.2014
2 1 2.2014
2 0 3.2014
2 0 4.2014
2 1 5.2014
2 0 6.2014
2 0 7.2014
2 1 8.2014
2 0 9.2014
;
run;
data want;
set have;
by id;
if first.id then do;n=0;x1=.;x2=.;x3=.;end;
if flag=1 then n+1;
if n ge 1 then do;x1+1;month1=cats('m',x1);end;
if n ge 2 then do;x2+1;month2=cats('m',x2);end;
if n ge 3 then do;x3+1;month3=cats('m',x3);end;
drop n x1 x2 x3;
run;
Look at the LAG function.
The following code works for your sample data.
data have(drop=_:);
infile datalines dlm=' ' truncover;
input ID Flag:$1. _date_str:$7.;
date=mdy(scan(_date_str,1),'01',scan(_date_str,2));
format date yymm7.;
datalines;
1 1 1.2014
1 0 2.2014
1 0 3.2014
1 1 4.2014
1 0 5.2014
1 0 6.2014
1 1 7.2014
1 0 8.2014
1 0 9.2014
1 0 10.2014
2 1 2.2014
2 0 3.2014
2 0 4.2014
2 1 5.2014
2 0 6.2014
2 0 7.2014
2 1 8.2014
2 0 9.2014
;
run;
%let rel_mth_arr_size=3;
data want(drop=_:);
set have;
by id date;
array rel_mth_ {&rel_mth_arr_size} 8.;
if first.id then call missing(of rel_mth_(*));
do _i=1 to dim(rel_mth_) while(not missing(rel_mth_(_i)));
rel_mth_(_i)+1;
end;
if flag='1' then
do _i=1 to dim(rel_mth_);
if missing(rel_mth_(_i)) then
do;
rel_mth_(_i)=1;
leave;
end;
end;
run;
Thanks alot for your time. This is very helpful
data have;
infile datalines dlm=' ' truncover;
input ID Flag date : $20.;
datalines;
1 1 1.2014
1 0 2.2014
1 0 3.2014
1 1 4.2014
1 0 5.2014
1 0 6.2014
1 1 7.2014
1 0 8.2014
1 0 9.2014
1 0 10.2014
2 1 2.2014
2 0 3.2014
2 0 4.2014
2 1 5.2014
2 0 6.2014
2 0 7.2014
2 1 8.2014
2 0 9.2014
;
run;
data want;
set have;
by id;
if first.id then do;n=0;x1=.;x2=.;x3=.;end;
if flag=1 then n+1;
if n ge 1 then do;x1+1;month1=cats('m',x1);end;
if n ge 2 then do;x2+1;month2=cats('m',x2);end;
if n ge 3 then do;x3+1;month3=cats('m',x3);end;
drop n x1 x2 x3;
run;
Good news: We've extended SAS Hackathon registration until Sept. 12, so you still have time to be part of our biggest event yet – our five-year anniversary!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.