I was able to use the code belwo to batch process files with names like 201501.csv, 201502.csv,.. etc
Now I have 12 files, whose names are named by months, like xxxx-Jan2014.csv, xxxx-Feb2014.csv, ... xxxx-Dec2014.csv.
Is there a way to use the similar code below?
%macro run_me;
%let n=1;
%do %while (&n <= 9);
%let filein = xxxx20150&n..csv;
data output&n;
infile &filein;
<data step-->
run;
%let n=%eval(&n+1);
%end;
%mend;
Yes, but you have to process over a list of values, rather than a range of numbers. You might call the macro like this:
%run_me (month_list=Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec)
Here's an article that tells you how to do it:
Yes, but you have to process over a list of values, rather than a range of numbers. You might call the macro like this:
%run_me (month_list=Jan Feb Mar Apr May Jun Jul Aug Sep Oct Nov Dec)
Here's an article that tells you how to do it:
Or you could step over months numerically and generate the part of the file name:
%let monnum=1;
%let year=2014;
%let name = %sysfunc(putn(%sysfunc(mdy(&monnum,1,&year)),MONYY7.));
%put &name;
If you have a do loop on MONNUM (or use &i where I used &monnum) you create the name part for a series.
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.