What does trim(put(mbrDes,$CON.)) generates?

[GN0001]

Hello team,

I have the code below:

I want to know why this part: trim(put(mbrDes,$CON.)) equals to DSS, it doesn't get equal to whole string. 

The code below doesn't generate errors: 

proc format;
values $CON
'b' = 'DSS- PP'
Run;

Data want (Keep = mbrDes);
format LineofBu $60. system $5;
set have;
LineofBu =trim(put(mbrDes,$CON.));
if LineofBu =: 'DSS' Then system = 'DSS';
run;

Regards,

blueblue

[PaigeMiller · Accepted solution]

The semicolon after the = sign in this line of code

if LineofBu =: 'DSS' Then system = 'DSS';

indicates that the test checks to see if the value of LineofBu starts with DSS (it does not test if the entire string is equal to DSS)

[Reeza]

FYI - your code as posted does generate errors for me - there are three syntax errors in your code.