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pankak
Calcite | Level 5

I have a data set given below:

data have;

input x y z a b c;

datalines;

1 2 3 4 . .

5 8 9 1 2 3

1 4 7 8 5 6

4 5 6 7 8 9

.  .  .  . 5 6

run;

The two values of first row is showing in the last row and four values of first row are missing in the last row.

I want correct missing values  in one row either first or last and remove the duplicate.

output like below.

x y z a b c

1 2 3 4 5 6. .

5 8 9 1 2 3

1 4 7 8 5 6

4 5 6 7 8 9

Thaks in advance.

6 REPLIES 6
Reeza
Super User

How do you know that you need to use first/last row to fix missing? Is it a single manual process?

pankak
Calcite | Level 5

Ok..Then do it for both Row..both first and last and place the correct values in that..I want only correct data..

naveen_srini
Quartz | Level 8

data have;

input x y z a b c;

datalines;

1 2 3 4 . .

5 8 9 1 2 3

1 4 7 8 5 6

4 5 6 7 8 9

. . . . 5 6

run;

data want;

set have end=last;

array arrayname _numeric_;

array arrayname2(*) x1 y2 z2 a2 b2 c2;

retain arrayname2;

if _n_=1 then do;

do i=1 to dim(arrayname);

arrayname2(i)=arrayname(i);

end;

              end;

if last then do;

if b2=. then b2=b;

if c2=. then c2=c;

output;

           end;

           keep  x1 y2 z2 a2 b2 c2;

run;

data want2;

set have;

if _n_=1 then set want;

array arrayname(*) x y z a b c;

array arrayname2(*) x1 y2 z2 a2 b2 c2;

do i=1 to dim(arrayname);

if arrayname(i)=. then arrayname(i)=arrayname2(i);

end;

keep  x y z a b c;

run;

Is this what you want?

Reeza
Super User

How do you know what's correct? Why isn't the missing filled in by the second row, why the last?

And why is the last filled in by the first? Or is it because they're missing opposite variables? Is there an ID variable to identify these rows?

If the business logic is simply for these two rows then do it manually

data have;

input x y z a b c;

datalines;

1 2 3 4 . .

5 8 9 1 2 3

1 4 7 8 5 6

4 5 6 7 8 9

.  .  .  . 5 6

;

run;

data want;

set have end=last;

if _n_=1 then do;

  b=5; c=6;

end;

if not last then output;

run;

stat_sas
Ammonite | Level 13

data want;

set have;

count=0;

array v _numeric_;

do over v;

if v=. then count+1;

end;

if count>0 then n=1;

else n=_n_;

run;

proc sql;

create table final as

select sum(x) as x,sum(y) as y, sum(z) as z, sum(a) as a,sum(b) as b, sum(c) as c

from want

group by n;

quit;

Ksharp
Super User
data have;
input x y z a b c;
datalines;
1 2 3 4 . .
5 8 9 1 2 3
1 4 7 8 5 6
4 5 6 7 8 9
.  .  .  . 5 6
;
run;
data want;
 set have end=last;
 if _n_ eq 1 then do;
  set have(rename=(x=_x y=_y z=_z a=_a b=_b c=_c)) nobs=nobs point=nobs;
  x=coalesce(x,_x);
  y=coalesce(y,_y);
  z=coalesce(z,_z);
  a=coalesce(a,_a);
  b=coalesce(b,_b);
  c=coalesce(c,_c);
 end;
 if not last;
 drop _:;
run;



Xia Keshan

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