Hi Everyone,
In my original code below, SAS processes all rows.
However, I only want SAS to process rows with day_of_interest=1.
I put %IF into the code but it doesn't work.
(In my actual work, it is a marco process)
Can anyone please help me to fix it?
Thank you,
HHC
data have;
input id sale max min day_of_interest;
datalines;
1 5 70 4 0
2 2 70 4 0
3 10 30 4 1
4 100 50 17 1
5 15 50 14 0
;run;
data want;
set have nobs=totalobs;
drop i new_id new_max new_min;
exit_id=.;
i+1;
do j=i+1 to totalobs until (exit_id^=.);
set have (keep = id max min rename=(id=new_id max=new_max min=new_min)) point=j;
if sale>new_max or sale<new_min then exit_id=new_id;
end;
run;
*------------MACRO----------------------;
%Macro xx;
data want;
set have nobs=totalobs;
exit_id=.;
i+1;
%IF day_of_interest=1 %THEN %DO;
do j=i+1 to totalobs until (exit_id^=.);
set have (keep = id max min rename=(id=new_id max=new_max min=new_min)) point=j;
if sale>new_max or sale<new_min then exit_id=new_id;
end;
%END;
run;
%MEnd;
%xx;
@hhchenfx wrote:
My real work is a macro, so I make this to replicate the situation.
That doesn't mean you have to use the macro %IF in this specific situation, especially since it will not work here. A macro %IF cannot evaluate the value of a data step variable to see if its value is equal to 1, as you are using here. A data step IF can evaluate the value of the data step variable to see if it is equal to 1.
Try using DATA step IF THEN ELSE instead of macro %IF %THEN %ELSE
My real work is a macro, so I make this to replicate the situation.
Thanks,
HHC
@hhchenfx wrote:
My real work is a macro, so I make this to replicate the situation.
That doesn't mean you have to use the macro %IF in this specific situation, especially since it will not work here. A macro %IF cannot evaluate the value of a data step variable to see if its value is equal to 1, as you are using here. A data step IF can evaluate the value of the data step variable to see if it is equal to 1.
1. The macro language should only be used when necessary, as it can confuse untrained users.
2. A trained user would know that the macro processor cannot know the value of a data step variable.
Hence @PaigeMiller 's valid recommendatoin.
Thank you all for helping.
I got it
data want;
set have nobs=totalobs;
drop i new_id new_max new_min;
exit_id=.;
i+1;
if day_of_interest=1 then do;
do j=i+1 to totalobs until (exit_id^=.);
set have (keep = id max min rename=(id=new_id max=new_max min=new_min)) point=j;
if sale>new_max or sale<new_min then exit_id=new_id;
end;
end;
run;
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