Data river_flow;
input dailyflow flowdate:date9. mymonth myday myyear quarterflow halfflow threequarterflow;
format flowdate date9.;
datalines;
1360.66 01JAN1940 1 1 1940 420185.91 840371.83 1260557.74
1382.48 02JAN1940 2 1 1940 420185.91 840371.83 1260557.74
1392.40 03JAN1940 3 1 1940 420185.91 840371.83 1260557.74
1404.30 04JAN1940 4 1 1940 420185.91 840371.83 1260557.74
1392.40 05JAN1940 5 1 1940 420185.91 840371.83 1260557.74
1348.76 06JAN1940 6 1 1940 420185.91 840371.83 1260557.74
1313.06 07JAN1940 7 1 1940 420185.91 840371.83 1260557.74
1328.93 08JAN1940 8 1 1940 420185.91 840371.83 1260557.74
1348.76 09JAN1940 9 1 1940 420185.91 840371.83 1260557.74
1372.56 10JAN1940 10 1 1940 420185.91 840371.83 1260557.74
1221.82 11JAN1940 11 1 1940 420185.91 840371.83 1260557.74
1128.59 12JAN1940 12 1 1940 420185.91 840371.83 1260557.74
1221.82 13JAN1940 13 1 1940 420185.91 840371.83 1260557.74
What is your requirement?and what's the logic for the requirement and more info please
I clearly stated what my goal is and provided a program with data that is almost there. I don't think I can be any more specific.
@Hydro1 Thank you and I do not disagree. My mind seems dumb to not grasp the logic nor the requirement well. I am sorry, however I am sure somebody will respond with a much needed solution and hopefully sooner. Hang in there
Yes. Sorry--I thought I had the text in the window. My goal is to output the date at which 25% , 50%, and 75% of the total annual volume of runoff is reach for each year in the dataset. The dataset contains daily flow (volume in acre-feet) , date, and the previously computed values of Q25, Q50, and Q75. The program contains the data and was slightly modified from that provided by HB.
Sincerely,
Hydro1
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