I want to remove leading zero and trailing zero, so I want to modify my variable by doing below:
var2 = strip(var1,'0');
I got the error message:
The STRIP function call has too many arguments.
anybody helps to solve this?
thanks
Unfortunately STRIP() does not have that function. For details, please refer strip function
For your problems, you can either try using a combination of multiple functions/multiple steps, Or using PRX function in one shot:
DATA HAVE;
INPUT STR $20.;
CARDS;
0012200
00023
22000
200340
;
DATA WANT;
SET HAVE;
NEW_STR=PRXCHANGE('s/^ *0*|0* *$//io', -1, str);
run;
Unfortunately STRIP() does not have that function. For details, please refer strip function
For your problems, you can either try using a combination of multiple functions/multiple steps, Or using PRX function in one shot:
DATA HAVE;
INPUT STR $20.;
CARDS;
0012200
00023
22000
200340
;
DATA WANT;
SET HAVE;
NEW_STR=PRXCHANGE('s/^ *0*|0* *$//io', -1, str);
run;
Are you ready for the spotlight? We're accepting content ideas for SAS Innovate 2025 to be held May 6-9 in Orlando, FL. The call is open until September 25. Read more here about why you should contribute and what is in it for you!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.