Summary statistics table

[hhchenfx]

Hi,

I want to create a table where each column is a variable.

Rows are Mean, Median, percentile 15, percentile 85, percentile x.

For mean and median, I can do it as below. 

However, when it come to percentile, I can't specify the output name as for mean and median so I am kind of stuck.

Can you please help?

Thank you,

HHC

data have;
input v0 v1 v2 v3 v4 v5;
datalines;
1 1 0 5 6 0
1 1 0 5 7 1
2 1 0 5 7 0
4 1 1 5 6 1
5 1 0 5 6 0
6 1 1 5 9 0
7 1 0 5 2 -1
8 2 1 5 4 -1
9 2 1 5 1 0
;run;


proc univariate data=have noprint;
var v0-v5;
output out=stat_1 
mean=v0-v5;run;
data stat_1; set stat_1;
statistic = 'MEAN';run;

proc univariate data=have noprint;
var v0-v5;
output out=stat_2 
median=v0-v5;run;
data stat_2; set stat_2;
statistic = 'MEDIAN';run;

*I can stack one on top of the other as name are the same;
data summary; set stat_1 stat_2;run;


proc univariate data=have noprint;
var v0-v5;
output out=stat_2 
pctlpts= 15
pctlname=v0-v5; *this doesn't work;
run;

[ballardw · Accepted solution]

If you want multiple percentiles for multiple variables see the following. Either of the Pcntlpre statements will work.
The key bit you were missing is PCNTLPRE, as in a prefix to put before things, especially when really wanting multiple percentiles. The list options a pretty limited. However I would not recommend the simple v0-v5 list if you are asking for many percentiles for many variables as it can get hard to tell where a base variable name ends and the percentile value starts.

proc univariate data=have noprint;
   var v0-v5;
   output out=stat_2 
   pctlpts= 15 30
   pctlpre = v0 - v5 
/*   pctlpre = Pv0_ Pv1_ Pv2_ Pv3_ Pv4_ Pv5_ */
   ;
run;

If you don't really need P15 or P85 you might look at this output from Proc tabulate:

proc tabulate data=have;
  var  v0-v5;
  table mean median p1 p10 p80 p90 p99 ,
        v0-v1
  ;
run;

Unfortunately Tabulate only does 1, 5, 10 to 90 by 10, 95 and 99 percentiles  and the quartiles ( q1=P25, q3 = P75)

[hhchenfx]

Thank you for your help.

HHC