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morichard
Calcite | Level 5

Hi,

How can i add count rows by groups through proc sql AND THEN (this is the key thing I can't find instructions on) create a new "total" variable that is the same for each member of the group -- NOT just the Last member of the group. In conceptual terms, I want each group member to know how many members of its group have x=1. 

 

Have dataset

x y n

0 a 0

1 a 1

0 b 0

1 b 1

1 b 2

0 c 0

1 c 1

1 c 2

1 c 3

 

wanted output 

x y n n2

0 a 0 1

1 a 1 1

0 b 0 2

1 b 1 2

1 b 2 2

0 c 0 3

1 c 1 3

1 c 2 3

1 c 3 3

 

 

Grouping variable is y, the variable to be counted/totaled is x.

 

i know  how to do it with data step:

Proc sort data = have ; 

by y;

run;

 

data want;

set have;

by y;

if first.y then n =0;

n + x;

run;

 

 

2 REPLIES 2
mkeintz
PROC Star

Since you are bothering to sort the data set, here is a single data step solution to use that sorted data set  (changed "n+x" to "n2+x" below): 

 

data want;
  set have;
  by y;
  if first.y then n2 =0;
  n2 + x;
  if last.y;
  do until (last.y);
    set have;
    by y;
    output;
  end;
run;

There are two SET plus BY pairs.  So the first. and last. dummy variables appear to be paired with the most-recently-used SET/BY combination.

--------------------------
The hash OUTPUT method will overwrite a SAS data set, but not append. That can be costly. Consider voting for Add a HASH object method which would append a hash object to an existing SAS data set

Would enabling PROC SORT to simultaneously output multiple datasets be useful? Then vote for
Allow PROC SORT to output multiple datasets

--------------------------
ballardw
Super User

@morichard wrote:

Hi,

How can i add count rows by groups through proc sql AND THEN (this is the key thing I can't find instructions on) create a new "total" variable that is the same for each member of the group -- NOT just the Last member of the group. In conceptual terms, I want each group member to know how many members of its group have x=1. 

 

Have dataset

x y n

0 a 0

1 a 1

0 b 0

1 b 1

1 b 2

0 c 0

1 c 1

1 c 2

1 c 3

 

wanted output 

x y n n2

0 a 0 1

1 a 1 1

0 b 0 2

1 b 1 2

1 b 2 2

0 c 0 3

1 c 1 3

1 c 2 3

1 c 3 3

 

 

Grouping variable is y, the variable to be counted/totaled is x.

 

i know  how to do it with data step:

Proc sort data = have ; 

by y;

run;

 

data want;

set have;

by y;

if first.y then n =0;

n + x;

run;

 

 


For future reference please specify which variable(s) define a group. It really isn't nice to make us guess.

 

A possible solution if the values of X are only ever 0, 1 and possibly missing:

data have;
   input x y $ n;
datalines;
0 a 0
1 a 1
0 b 0
1 b 1
1 b 2
0 c 0
1 c 1
1 c 2
1 c 3
;

proc sql;
   create table want as 
   select x,y,n, sum(x) as n2
   from have
   group by y
   ;
quit;

There will be a note in the log:

NOTE: The query requires remerging summary statistics back with the original data.

which is because it is doing exactly what you request: merging a single summary statistic (the sum of X) to all of the rows of the group.

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