Hi Team,
I am currently working on a dataset where the Chattext
column contains a long string of text that I need to split into multiple lines, as demonstrated in the desired output format below:
Attached file with input data and desired output results I'm looking for.
Thanks in Advance!
Looks like you split the example some how, what logic did you use? Why did you split it at those locations? Explain the rule.
Did you try any SAS code? How well did it work?
PS No need to attach a file. You can post simple text using the Insert Code button to get a pop-up window.
Chat_id Chattext 101 10/05/2024 10:15:00 krishna.vangalli@gmail.com hello Raju how are you 10/05/2024 10:16:15 Raju@gmail.com Hey krishna whatsup I'm doing good 102 10/06/2024 11:15:00 krish.vangalli@gmail.com hello 10/06/2024 10:16:15 Raju@gmail.com Hey krishna whatsup I'm doing good
data have;
infile cards truncover;
input Chat_id Chattext $200.;
cards;
101 10/05/2024 10:15:00 krishna.vangalli@gmail.com hello Raju how are you 10/05/2024 10:16:15 Raju@gmail.com Hey krishna whatsup I'm doing good
102 10/06/2024 11:15:00 krish.vangalli@gmail.com hello 10/06/2024 10:16:15 Raju@gmail.com Hey krishna whatsup I'm doing good
;
data want;
set have;
pid=prxparse('/\d+\/\d+\/\d+/');
s=1;e=length(Chattext);
call prxnext(pid,s,e,Chattext,p,l);
do while(p>0);
_p=p;
call prxnext(pid,s,e,Chattext,p,l);
if p>0 then temp=substr(Chattext,_p,p-_p);
else temp=substr(Chattext,_p);
date=scan(temp,1,,'s');
time=scan(temp,2,,'s');
sender=scan(temp,3,,'s');
call scan(temp,3,p2,l2,,'s');
chat_text=substr(temp,p2+l2);
output;
end;
keep Chat_id date time sender chat_text ;
run;
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