| Date | price |
| 19890731 | 1.981 |
| 19900731 | 1.287 |
| 19910731 | 1.792 |
| 19921231 | 7.271 |
| 19931231 | 13.017 |
| 19941231 | 22.317 |
| 19981231 | 27.857 |
| 19991231 | 26.242 |
| 20001231 | 35.12 |
| 20011231 | 12.808 |
| 20021231 | 11.907 |
| 19901231 | 5.656 |
| 19911231 | 3.85 |
From the above data I want to keep data related 31st December. So, I need code for YR1231. Please help
Could you please try this ?
data have2;
set have;
format date2 date9.;
date2 = input(put(date,8.),yymmdd8.); /* Date2 = date in a date format*/
run;
HI @abdulla ,
Maybe this is something you can try:
data have;
input Date yymmdd8. price;
format Date date9.;
cards;
19890731 1.981
19900731 1.287
19910731 1.792
19921231 7.271
19931231 13.017
19941231 22.317
19981231 27.857
19991231 26.242
20001231 35.12
20011231 12.808
20021231 11.907
19901231 5.656
19911231 3.85
;
run;
data want;
set have;
where month(date)=12 and day(date)=31;
run;Hope this help.
Hi, is your file already a SAS dataset?
Perfect. And what is the type of the Date variable? (Num or Char). Is it already recognize as a date ?
OK. I encourage you to check the variable type / format / etc. by using a proc contents:
proc contents data=have;
run;If it is a character variable, you will a have to convert it using the input() function or the substr() function depending if you need to have this variable as a date.
If it is a numeric variable, you will a have to apply a date format.
Could you please try this ?
data have2;
set have;
format date2 date9.;
date2 = input(put(date,8.),yymmdd8.); /* Date2 = date in a date format*/
run;
Awesome! Have a great day.
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