BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
scb
Obsidian | Level 7 scb
Obsidian | Level 7

 

In the below dataset A, I have 4 names with ID numbers, may I know how to create new ID for the new names in dataset, from 1008 to 1011? Below is sample only, i could have thousands of new names.

 

DATA A;
INFILE CARDS;
INPUT ID NAME $;
CARDS;
1004 JESSICA
1005 UTAKA
1006 MORRISSON
1007 NELSON
;
RUN;


DATA B;
INFILE CARDS;
INPUT NAME $;
CARDS;
RYAN
HOLLY
MASON
DORREN
;
RUN;

1 ACCEPTED SOLUTION

Accepted Solutions
Reeza
Super User

Data want;

set a(in=AI)

      B(in=BI);

 

retain maxid count 0;

if AI and id>MaxID then maxID=ID;

if BI then Do;

count+1;

ID=maxID + count;

end;

run;

 

This can possibly be simplified massively but it's easy to understand. 

 

Edit: fixed typo. Also, this is untested. 

View solution in original post

3 REPLIES 3
Reeza
Super User

Are you using solely SAS? Many DBs have auto-incrementing IDs which is why I ask. 

 

scb
Obsidian | Level 7 scb
Obsidian | Level 7

Yes, SAS only. 

Reeza
Super User

Data want;

set a(in=AI)

      B(in=BI);

 

retain maxid count 0;

if AI and id>MaxID then maxID=ID;

if BI then Do;

count+1;

ID=maxID + count;

end;

run;

 

This can possibly be simplified massively but it's easy to understand. 

 

Edit: fixed typo. Also, this is untested. 

sas-innovate-2026-white.png



April 27 – 30 | Gaylord Texan | Grapevine, Texas

Registration is open

Walk in ready to learn. Walk out ready to deliver. This is the data and AI conference you can't afford to miss.
Register now and lock in 2025 pricing—just $495!

Register now

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

SAS Training: Just a Click Away

 Ready to level-up your skills? Choose your own adventure.

Browse our catalog!

Discussion stats
  • 3 replies
  • 1358 views
  • 0 likes
  • 2 in conversation