SAS intnx function query

[scb]

In the below code, I can get 2018 for variable A and 2019 for variable B.  May I know how to get 2018/2019 for variable C? Thanks.

%LET RUNDATE = TODAY();

data  _null_;
call symput("A",put(intnx('YEAR',&RUNDATE,-1),YEAR4.));
call symput("B",put(intnx('YEAR',&RUNDATE,0),YEAR4.));
run;

%PUT A = &A;
%PUT B = &B;

[RW9]

Yes, bur first off, please avoid shouting code at us, and finish macro variables with a dot, use the code window, and indentations!!

data  _null_;
  a=put(intnx('year',today(),-1),year4.);
  b=put(intnx('year',today(),0),year4.);
  call symput("A",a);
  call symput("B",b);
  call symput("C",catx('/',a,b));
run;

%put A=&a.;
%put B=&b.;
%put C=&c.;

The next question is, why put the today() result in a macro variable at all, or in fact the other two data items?  Each of these elements can simply be found by querying the today() function at the appropriate moment?

[Astounding]

Once you have this much:

%LET RUNDATE = TODAY();

data  _null_;
call symput("A",put(intnx('YEAR',&RUNDATE,-1),YEAR4.));
run;

That lets you continue with:

%let B = %eval(&A + 1);

%let C = &A/&B;