Hi,
I have the below dataset
data have;
input original_date $50.;
datalines;
Mon Mar 11 12:01:41 UTC 2024
;
run;
Need a new column (string) with the original date in the format yyyy-mm-ddThh:mm:ssZ.
How can this be done. Thank you
What did you try? What datetime value do you think that string represents?
Try this:
data have;
input _Dow:$3. _M:$3. _D _T:$8. _Z:$3. _Y;
Original_date=_infile_;
Datetime_string=cats(put(_D,2.),_M,put(_Y,4.),'T',_t,_Z);
drop _:;
datalines;
Mon Mar 11 12:01:41 UTC 2024
;
run;
You will probably need to use SCAN() to break that string into its pieces so you can combine them together in the right way to make datetime value.
Example:
data have;
input original_date $50.;
datalines;
Mon Mar 11 12:01:41 UTC 2024
;
data want;
set have;
dayname=scan(original_date,1,' ');
monname=scan(original_date,2,' ');
day=input(scan(original_date,3,' '),?32.);
tod=input(scan(original_date,4,' '),time24.);
tz=scan(original_date,5,' ');
system_tz = getoption('timezone');
year=input(scan(original_date,6,' '),?32.);
date=input(cats(day,monname,year),date9.);
datetime=dhms(date,0,0,tod);
offset = tzoneoff(tz,datetime);
format tod tod8. date date9. datetime E8601dt.;
put (_all_) (=/);
run;
Result
original_date=Mon Mar 11 12:01:41 UTC 2024 dayname=Mon monname=Mar day=11 tod=12:01:41 tz=UTC system_tz= year=2024 date=11MAR2024 datetime=2024-03-11T12:01:41 offset=0
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