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AndreasF
Fluorite | Level 6

Dear all,

 

Maybe you have a quick solution for this: 

I would like to create a timeseries for 48 months. Always get month end by providing a start date via a macro variable. My code below doesn't work. Any ideas?

So, Reporting_Date should look like:

31jan2020

29feb2020

31mar2020

...

 

%let startdate = '01jan2020'd;

data test;
 do t = 1 to 48;
  Reporting_Date = intnx('month', '&startdate.', t-1, 'E');
  output;
 end;
run;

 

Thanks!

 

1 ACCEPTED SOLUTION

Accepted Solutions
Kurt_Bremser
Super User

First of all, macro variables are not resolved when enclosed in single quotes. Second, you already have quotes in your macro variables, so that won't work either. Third, without a date format your results will not display right.

So do this:

%let startdate = 01jan2020;

data test;
format Reporting_Date yymmddd10.;
 do t = 1 to 48;
  Reporting_Date = intnx('month', "&startdate."d, t-1, 'E');
  output;
 end;
run;

View solution in original post

1 REPLY 1
Kurt_Bremser
Super User

First of all, macro variables are not resolved when enclosed in single quotes. Second, you already have quotes in your macro variables, so that won't work either. Third, without a date format your results will not display right.

So do this:

%let startdate = 01jan2020;

data test;
format Reporting_Date yymmddd10.;
 do t = 1 to 48;
  Reporting_Date = intnx('month', "&startdate."d, t-1, 'E');
  output;
 end;
run;

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