Hi All,
I have the following dataset
data have;
input reporting_date account_id $ repayment_type $;
informat reporting_date date9.;
format reporting_date date9.;
cards ;
31JAN2018 123 REP
31JAN2018 456 INT
31JAN2018 789 PAP
28FEB2018 123 REP
28FEB2018 456 .
28FEB2018 789 PAP
31MAR2018 123 .
31MAR2018 456 .
31MAR2018 789 .
;
run;
What I need to get to is
Reporting_Date | Account_ID | Repayment_Type |
31-Jan-18 | 123 | REP |
31-Jan-18 | 456 | INT |
31-Jan-18 | 789 | PAP |
28-Feb-18 | 123 | REP |
28-Feb-18 | 456 | INT |
28-Feb-18 | 789 | PAP |
31-Mar-18 | 123 | REP |
31-Mar-18 | 456 | INT |
31-Mar-18 | 789 | PAP |
I need to retain the repayment type only if the repayment type is missing the following month.
Regards
Adnan
Thats very simple, did you read the examples in the SAS docs?
Maybe something like:
data want; set have; retain lst; if lst ne "" then lst=repayment_type; else repayment_type=lst; run;
data have;
input reporting_date account_id $ repayment_type $;
informat reporting_date date9.;
format reporting_date date9.;
cards ;
31JAN2018 123 REP
31JAN2018 456 INT
31JAN2018 789 PAP
28FEB2018 123 REP
28FEB2018 456 .
28FEB2018 789 PAP
31MAR2018 123 .
31MAR2018 456 .
31MAR2018 789 .
;
run;
data want;
set have ;
by reporting_date;
if first.reporting_date then n=0;
n+1;
if n=1 then repayment_type='REP';
if n=2 then repayment_type='INT';
if n=3 then repayment_type='PAP';
drop n;
run;
Good news: We've extended SAS Hackathon registration until Sept. 12, so you still have time to be part of our biggest event yet – our five-year anniversary!
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.