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tropical_surfer
Fluorite | Level 6

How can I remove only the 2nd space in a string?

 

1 ACCEPTED SOLUTION

Accepted Solutions
Ksharp
Super User
data _null_;
x='xxx yyy zzz';
call scan(x,3,p,l,' ');
want=substr(x,1,p-2)||substr(x,p);
put x= want=;
run;

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4 REPLIES 4
Astounding
PROC Star

There may be easier ways.

 

It may be that this is not what you really want.  Remember, you are only shifting text over since the length of a character variable is fixed.

 

You may be better served by the COMPBL function.

 

WIth all that in mind, here is a way to approach what you asked for:

 

data want;

set have;

blanks=0;

if string > ' ' then do i=1 to length(string) until (blanks=2);

  if substr(string, i, 1)=' ' then blanks + 1;

end;

if blanks=2 then string = substr(string, 1, i-1) || substr(string, i+1);

run;

 

I also tried looking at CALL SCAN, but didn't find an approach that seemed like it would work.

PGStats
Opal | Level 21

Given the string

 

AsBsCssD

 

where s is a space, do you want

 

AsBCssD  (second space of the string removed)

 

or

 

AsBsCsD  (double space replaced by single space) ?

PG
Patrick
Opal | Level 21

What does "2nd space" mean? The 2nd occurence of a space or just don't have consecutive spaces?

 

For "not consecutive spaces" I'd use function "compbl()"

 

 

Ksharp
Super User
data _null_;
x='xxx yyy zzz';
call scan(x,3,p,l,' ');
want=substr(x,1,p-2)||substr(x,p);
put x= want=;
run;

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