I am trying to find data that is 7 digits long and start with the number 4.
data want; if not prxId then prxId + prxParse("/\d{7}\/"); set CV_misscr14; start = 1; stop = length(aj_text); call prxNext(prxID, start, stop, aj_text, pos, len); do while (pos > 0); cmaenum = input(prxPosn(prxId, 1, aj_text), best.); output; call prxNext(prxID, start, stop, aj_text, pos, len); end; /*drop prxId start stop pos len;*/ run;
What do I need to change here for it to search for that?
Hi @Kiteulf,
Your DO loop suggests that you anticipate the possibility of more than one match per value of aj_text. In this case just correct the regular expression to
/4\d{6}/
and the second argument of the PRXPOSN function to 0.
Then from, say,
aj_text='3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706'
you would obtain
cmaenum 4159265 4626433 4197169 4944592 4062862 4825342
data have;
input x $10.;
if prxmatch('/^4\d{6}$/',strip(x)) then found=1;
cards;
1234567890
3232ywrer67
4wewe786834
4586888
45678213
;
Hi @Kiteulf,
Your DO loop suggests that you anticipate the possibility of more than one match per value of aj_text. In this case just correct the regular expression to
/4\d{6}/
and the second argument of the PRXPOSN function to 0.
Then from, say,
aj_text='3.14159265358979323846264338327950288419716939937510582097494459230781640628620899862803482534211706'
you would obtain
cmaenum 4159265 4626433 4197169 4944592 4062862 4825342
It's finally time to hack! Remember to visit the SAS Hacker's Hub regularly for news and updates.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.
Ready to level-up your skills? Choose your own adventure.