Have a script that works great
proc import datafile="c:\temp\input.csv" replace /* out command below only keeps what var columns you need for data - missing vars represent empty columns */ out = data_read (keep = var1 var2 var4 var5 var11 var12) dbms=csv out=t2 ; guessingrows=32767 ; *getnames=yes - pulls the header names, only use if csv has headers namerow will also tell you what line to get the names if necessary; getnames=no ; *Firstobs=9; *datarow tells you what line to start; datarow=9 ; DELIMITER=' ' ; run ; proc contents ; run ; proc print ; run ; proc export data=t2 outfile="C:\temp\output.csv" dbms=csv replace ; run ;
The problem is that the the input.csv file now contains the following statement
" Elapsed: 00:14:43.61," at the end of the file
So I am looking for way to delete the last line or find a way to delete rows that beging with "elapsed"
Here is one possible solution: replace the first two lines of your script:
proc import datafile="c:\temp\input.csv"
with
filename FT16F001 temp; data _null_; infile "c:\temp\input.csv"; file FT16F001; input; if _infile_ eq: 'Elapsed' then stop; put _infile_; run;
proc import datafile=FT16F001
Art, CEO, AnalystFinder.com
Here is one possible solution: replace the first two lines of your script:
proc import datafile="c:\temp\input.csv"
with
filename FT16F001 temp; data _null_; infile "c:\temp\input.csv"; file FT16F001; input; if _infile_ eq: 'Elapsed' then stop; put _infile_; run;
proc import datafile=FT16F001
Art, CEO, AnalystFinder.com
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