Please Help with the error on Array "ERROR: Array subscript out of range at line ~ column ~ . "

[Lulus]

super wired, I actually then converted the income_dx to an income_dx2 and assign the 2nd one numeric type, the re-ran the loop, and the probem

moved down to line (plz see original) coding2(ETHG_dx)=1;

[Lulus]

I've got a great update.  Even it's not perfect yet.  However, now I am able to have the nested loop completed

EXCEPT!!

it wouldn't print out the missing element for me. 

So, ok the income_dx are all going to be my binary variables. 

so I have 6 columbs represent salary1 salary2 ....salary6 but just not the "missing", ok I changed the name to salary9, didn't work, and ok changed it again to salary7...................didn't work,either.

here is the error for my log.

ERROR: Array subscript out of range at line ~ column ~. and that's it.  None of my errors have rulers or something.

which is this line here, coding4(k)=0;  (???????)

Didn't I tell SAS PLEASE do 1 to 7?

What happened makes it just give me 6 columns (binary dummies variables)?

[TimArm]

Your earlier post said the income_dx values were 1,2,3,4,5,6, and 9

If you want to do coding4(income_dx) = 1;, then that is going to put something in coding(9) at some point.

Have you got somewhere for sas to put it?

Go back to declaring your array as salary1-salary10 and there will be a variable to store for coding(9).

Then you also need to make sure that you are looking at all of the values when you are retrieving/initialising the values i.e. do k=1 to 10; NOT do k=1 to 7;

Does that make sense?

[Reeza]

set stdff;

  array coding2 {*} agroup_1-agroup_6;

  do i=1 to 6;

       coding2(i)=0; /*i isn't used past this point but you're repeating the loop 6 times for what reason?????*/

       array coding3 {*} boys girls notdisclose nodata;

       do j=1 to 4;

       coding3(j)=0; /*j isn't used past this point but you're repeating the loop 4 times for what reason?????*/

  array coding4 {*} salary1-salary6 salary7;

  do k=1 to 7;

  coding4(k)=0;
/*k isn't used past this point but you're repeating the loop 7 times for what reason?????*/

  end;

  coding4(income_dx)=1;    <-------------------------------Error Happens Here!! Need help!!

  end;

  coding3(gndr_dx)=1;

  end;

  coding2(ETHG_dx)=1;

drop i j k;

run;

Your loops and code make no sense to me at all. And if you've define an array of 7 elements but call it with 9 then it's clearly out of range. Re-think whatever you're trying to do and give it another go...

[Astounding]

It sounds like you're looking for this:

coding4(min(7, income_dx))=1;

That way, when income_dx is 9, the MIN function returns 7 and the statement changes the 7th element of the array.

Sensible?

[Lulus]

Thank you very much.  I will try it.  Happy holidays all.

[TimArm]

min(7,income_dx)  -  that's an Astoundingly good suggestion. I like it.

I have another alternative, though - use a format to map the value of income_dx to an array index.

With a format you could catch values for income_dx that are not in 1,2,3,4,5,6,9 and assign them to another array index for data "errors". A format would also let you convert the character income_dx to a number without creating another variable.